From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

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 3750/CH19/EX19.1/Ex19_1.sce | 34 ++++++++++++++++++++++++++++++++++
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+//Strength Of Material By G.H.Ryder
+//Chapter 19
+//Example 1
+//To Find Maximum stress at the Fatigue limit for repeated stress conditions, according to Gerber's law and Goodman's Law
+
+clc();
+
+//Initialization of Variables
+SigmaU=600;  //Ultimate tension strength, Unit in N/mm^2
+El=180;//Endurance limit under reversed stress, Unit in N/mm^2
+
+//Computations
+// Under Reversed Stress
+M=0;  //B.M for reversed stress=0, Unit in K
+Sigma=El; //Unit in Unit in N/mm^2
+R=2*Sigma;   //Stress Range, N/mm^2
+n=SigmaU/R;  //By Gerber's Formula
+//Under Repeated stress
+   //R=Sigma
+   //M=Sigma/2
+   //Sigma=(SigmaU/n)*(1-M^2/SigmaU^2)
+//From Gerber's Law
+//Solving for quadatic in Sigma
+a=1, b=4*SigmaU*n,c=-4*SigmaU^2;
+Sigma=(-b+sqrt(b^2-4*c*a))/(2*a); //The answer vary due to round off error
+
+//Result1
+printf("The maximum stress at fatigue limit for repeated stress condition is :\n\t")
+printf("%.0f N/mm^2 According to Gerbers Law\n\t",Sigma)  //The answer vary due to round off error
+//According to Goodman's Law
+Sigma=(SigmaU/n)/(1+1/(2*n));    //The answer vary due to round off error
+
+//Result2
+printf("%.0f N/mm^2 According to Goodmans Law",Sigma)
-- 
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