From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 3718/CH5/EX5.1/Ex5_1.sce   | 11 +++++++++++
 3718/CH5/EX5.10/Ex5_10.sce | 17 +++++++++++++++++
 3718/CH5/EX5.11/Ex5_11.sce | 11 +++++++++++
 3718/CH5/EX5.12/Ex5_12.sce | 15 +++++++++++++++
 3718/CH5/EX5.2/Ex5_2.sce   | 11 +++++++++++
 3718/CH5/EX5.3/Ex5_3.sce   | 24 ++++++++++++++++++++++++
 3718/CH5/EX5.4/Ex5_4.sce   | 12 ++++++++++++
 3718/CH5/EX5.5/Ex5_5.sce   |  7 +++++++
 3718/CH5/EX5.6/Ex5_6.sce   | 16 ++++++++++++++++
 3718/CH5/EX5.7/Ex5_7.sce   | 12 ++++++++++++
 3718/CH5/EX5.8/Ex5_8.sce   | 16 ++++++++++++++++
 11 files changed, 152 insertions(+)
 create mode 100644 3718/CH5/EX5.1/Ex5_1.sce
 create mode 100644 3718/CH5/EX5.10/Ex5_10.sce
 create mode 100644 3718/CH5/EX5.11/Ex5_11.sce
 create mode 100644 3718/CH5/EX5.12/Ex5_12.sce
 create mode 100644 3718/CH5/EX5.2/Ex5_2.sce
 create mode 100644 3718/CH5/EX5.3/Ex5_3.sce
 create mode 100644 3718/CH5/EX5.4/Ex5_4.sce
 create mode 100644 3718/CH5/EX5.5/Ex5_5.sce
 create mode 100644 3718/CH5/EX5.6/Ex5_6.sce
 create mode 100644 3718/CH5/EX5.7/Ex5_7.sce
 create mode 100644 3718/CH5/EX5.8/Ex5_8.sce

(limited to '3718/CH5')

diff --git a/3718/CH5/EX5.1/Ex5_1.sce b/3718/CH5/EX5.1/Ex5_1.sce
new file mode 100644
index 000000000..f304c4437
--- /dev/null
+++ b/3718/CH5/EX5.1/Ex5_1.sce
@@ -0,0 +1,11 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 1
+clc;
+
+//Declaration of Variables
+K = 3.5 * 10 ** - 2             // Rate constant
+
+// Solution
+mprintf("First order reaction = 0.693 / K\n")
+t = 0.693 / K
+mprintf(" Time taken for half the initial concentration to react:%.1f minutes", t)
diff --git a/3718/CH5/EX5.10/Ex5_10.sce b/3718/CH5/EX5.10/Ex5_10.sce
new file mode 100644
index 000000000..f483081ff
--- /dev/null
+++ b/3718/CH5/EX5.10/Ex5_10.sce
@@ -0,0 +1,17 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 10
+clc;
+
+//Declaration of Constant
+R = 1.987               //in cal per K per mol
+
+//Declaration of Variables
+K2_K1 = 4    // factor increase
+T1 = 27      //in C
+T2 = 47      //in C
+
+// Solution
+T1 = T1 + 273.0
+T2 = T2 + 273.0
+Ea = log10(4) * 2.303 * R * (T1 * T2 / (T2 - T1))
+mprintf("The activation energy for the reaction is %.2e cal /mol",Ea)
diff --git a/3718/CH5/EX5.11/Ex5_11.sce b/3718/CH5/EX5.11/Ex5_11.sce
new file mode 100644
index 000000000..4f03204d2
--- /dev/null
+++ b/3718/CH5/EX5.11/Ex5_11.sce
@@ -0,0 +1,11 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 11
+clc;
+
+//Declaration of Variables
+a = 1          //in mole
+x = 3 / 4.0    // reaction completed
+
+// Solution
+K = (2.303 / 6) * log10(1 / (1 - x))
+mprintf("The rate constant is :%.3f / min",K)
diff --git a/3718/CH5/EX5.12/Ex5_12.sce b/3718/CH5/EX5.12/Ex5_12.sce
new file mode 100644
index 000000000..21a720919
--- /dev/null
+++ b/3718/CH5/EX5.12/Ex5_12.sce
@@ -0,0 +1,15 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 12
+clc;
+
+// Solution
+mprintf("Let the initial concentration be 100, when x = 25,t = 30 minutes\n")
+a = 100
+x = 25.0
+t = 30
+K = 2.303 / t * log10(a / (a - x))
+t05 = 0.683 / K
+t = 2.303 / K * log10(a / x)
+mprintf(" K = %.2e / min\n",K)
+mprintf(" T0.5 = %.2f min\n",t05)
+mprintf(" t = %.1f min",t)
diff --git a/3718/CH5/EX5.2/Ex5_2.sce b/3718/CH5/EX5.2/Ex5_2.sce
new file mode 100644
index 000000000..04c757c80
--- /dev/null
+++ b/3718/CH5/EX5.2/Ex5_2.sce
@@ -0,0 +1,11 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 2
+clc;
+
+//Declaration of Variables
+t = 40      //in minutes
+
+// Solution
+mprintf("Rate constant = 0.693 / t\n")
+K = 0.693 / t
+mprintf(" Rate constant = %.4f / min",K)
diff --git a/3718/CH5/EX5.3/Ex5_3.sce b/3718/CH5/EX5.3/Ex5_3.sce
new file mode 100644
index 000000000..b95280d30
--- /dev/null
+++ b/3718/CH5/EX5.3/Ex5_3.sce
@@ -0,0 +1,24 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 3
+clc;
+
+//Declaration of Variables
+t0 = 37.0                   //in cm cube of KMnO4
+t5 = 29.8                   //in cm cube of KMnO4
+t15 = 19.6                  //in cm cube of KMnO4
+t25 = 12.3                  //in cm cube of KMnO4
+t45 = 5.00                  //in cm cube of KMnO4
+
+// Solution
+K5 = 2.303 / 5 * log10(t0 / t5)
+K15 = 2.303 / 15 * log10(t0 / t15)
+K25 = 2.303 / 25 * log10(t0 / t25)
+K45 = 2.303 / 45 * log10(t0 / t45)
+
+mprintf("At t = 5 min, K = %.3e /min\n",K5)
+mprintf(" At t = 15 min, K = %.3e /min\n",K15)
+mprintf(" At t = 25 min, K = %.3e /min\n",K25)
+mprintf(" At t = 45 min, K = %.3e /min\n",K45)
+mprintf(" As the different values of K are nearly same, the reaction is of first-order\n")
+K = (K45 + K25 + K5 + K15) / 4
+mprintf(" The average value of K = %.3e /min",K)
diff --git a/3718/CH5/EX5.4/Ex5_4.sce b/3718/CH5/EX5.4/Ex5_4.sce
new file mode 100644
index 000000000..019c82985
--- /dev/null
+++ b/3718/CH5/EX5.4/Ex5_4.sce
@@ -0,0 +1,12 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 4
+clc;
+
+//Declaration of Variables
+t = 60                  //in min
+x = "0.5a"
+K = 5.2 * 10 ** - 3     //in per mol L per min
+
+// Solution
+a = 1 / (t * K)
+mprintf("Initial concentration = %.3f mol / L",a)
diff --git a/3718/CH5/EX5.5/Ex5_5.sce b/3718/CH5/EX5.5/Ex5_5.sce
new file mode 100644
index 000000000..a7a1d537e
--- /dev/null
+++ b/3718/CH5/EX5.5/Ex5_5.sce
@@ -0,0 +1,7 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 5
+clc;
+
+// Solution
+t = ((2.303 * log10(100 / (100 - 99.9))) / (2.303 * log10(100 / (100 - 50))))
+mprintf("99.9 percent / 50 percent =%.1f",t)
diff --git a/3718/CH5/EX5.6/Ex5_6.sce b/3718/CH5/EX5.6/Ex5_6.sce
new file mode 100644
index 000000000..4bd645e2f
--- /dev/null
+++ b/3718/CH5/EX5.6/Ex5_6.sce
@@ -0,0 +1,16 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 6
+clc;
+
+//Declaration of Constants
+R = 1.987               //in cal per K per mol
+
+//Declaration of Variables
+T1 = 273.0              //in K
+T2 = 303.0              //in K
+K1 = 2.45 * 10 ** -5
+K2 = 162 * 10 ** -5
+
+// Solution
+Ea = log10(K2 / K1) * R * 2.303 / ((T2 - T1) / (T1 * T2))
+mprintf("The activation energy of the reaction is %d cal / mol",Ea)
diff --git a/3718/CH5/EX5.7/Ex5_7.sce b/3718/CH5/EX5.7/Ex5_7.sce
new file mode 100644
index 000000000..8c910d166
--- /dev/null
+++ b/3718/CH5/EX5.7/Ex5_7.sce
@@ -0,0 +1,12 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 7
+clc;
+
+//Declaration of Variables
+t05 = 30                //in minutes
+a = 0.1                 //in M
+
+// Solution
+mprintf("For second order reaction,\n t0.5 = 1 / Ka\n")
+K = 1 / (a * t05)
+mprintf(" The rate constant is %.3f mol per lit per min",K)
diff --git a/3718/CH5/EX5.8/Ex5_8.sce b/3718/CH5/EX5.8/Ex5_8.sce
new file mode 100644
index 000000000..bc995af68
--- /dev/null
+++ b/3718/CH5/EX5.8/Ex5_8.sce
@@ -0,0 +1,16 @@
+//Chapter 5: Chemical Kinetics and Catalysis
+//Problem: 8
+clc;
+
+//Declaration of Variables
+T = 500        //in C
+Pi = 350       //in torr
+r1 = 1.07      //in torr / s
+r2 = 0.76      //in torr / s
+
+// Solution
+mprintf("1.07 = k(0.95a)^n\n")
+mprintf(" 0.76 = k(0.80a)^n\n")
+n = log(r1 / r2) / log(0.95 / 0.80)
+n=ceil(n)
+mprintf(" Hence, order of reaction is %d",n)
-- 
cgit