From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 3685/CH22/EX22.10/Ex22_10.sce | 22 ++++++++++++++++++++++
 1 file changed, 22 insertions(+)
 create mode 100644 3685/CH22/EX22.10/Ex22_10.sce

(limited to '3685/CH22/EX22.10/Ex22_10.sce')

diff --git a/3685/CH22/EX22.10/Ex22_10.sce b/3685/CH22/EX22.10/Ex22_10.sce
new file mode 100644
index 000000000..7b2d0b22b
--- /dev/null
+++ b/3685/CH22/EX22.10/Ex22_10.sce
@@ -0,0 +1,22 @@
+clc
+// Given that
+l = 2 // Length of tube in m
+a = 1e-4 // Cross section of the tube in m^2
+p = 1 // Pressure in atm
+t = 0 // Temperature in degree centigrade
+r = 0.5 // Fraction of the carbon atoms which are radioactive C14
+sigma = 4e-19 // Collision cross section area in m^2
+printf("\n Example 22.10 \n")
+n = (p*1.01325e+5)/((1.38e-23)*(t+273))
+C_g = -n/l
+m = (46/6.023)*10^-26 // In kg/molecule
+v = (2.55*(1.38e-23)*(t+273)/m)^(1/2)
+lambda = (1/(sigma*n))
+gama = (1/4)*(v*n) - (1/6)*(v*lambda*(C_g))
+gama_ = (1/4)*(v*n) + (1/6)*(v*lambda*(C_g))
+x = (1/4)*(v*n)
+y = (1/6)*(v*lambda*(C_g))
+d = (1/6)*(v*lambda*(-1*C_g))*2*(m)
+printf("\n Initial concentration gradient of reactive molecules = %e molecules/m^4, \n The no of reactive molecules per sec cross a cross section at the mid point of the tube from left to right = %e - (%e) molecules/m^2,\n The no of reactive molecules per sec cross a cross section at the mid point of the tube from right to left = %e + (%e) molecule/m^2,\n Initial net rate of diffusion = %fg/m^2-s",C_g,x,y,x,y,d*1000)
+// The answer for lambda given in the book conatains calculation error
+// The answers contains calculation error
-- 
cgit