From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 3682/CH4/EX4.6/Ex4_6.sce | 21 +++++++++++++++++++++ 1 file changed, 21 insertions(+) create mode 100644 3682/CH4/EX4.6/Ex4_6.sce (limited to '3682/CH4/EX4.6') diff --git a/3682/CH4/EX4.6/Ex4_6.sce b/3682/CH4/EX4.6/Ex4_6.sce new file mode 100644 index 000000000..fadae8942 --- /dev/null +++ b/3682/CH4/EX4.6/Ex4_6.sce @@ -0,0 +1,21 @@ +// Exa 4.6 + +clc; +clear; + +// Given data + +//Referring circuit in Fig. 4.26 +// An op amp integrator and a low pass Rc circuit) + +// Solution + +printf(' Figure (4.26) is a simple op-amp integrator where Millers theorem is applied across the feedback capacitor Cf. \n The input time constant T = R1*Cf*(1-Av). \n Therefore, vi = V*(1-e^(-t/T));'); +printf(' \n Therefore, vo = Av*Vi = Av* V*(1-e^(-t/R1*Cf*(1-Av))); '); +printf(' \n By expanding e^(-t/..) series by Taylors Expansion method we will reach to following approximation'); +printf('\n vo ≈ (-V*t/R1*Cf) * [1- t/(2*R1*Cf*(1-Av))]; if Av>>1 ...eq (1) '); +printf('\n\n'); +printf(' Also, we know that for a low pass RC integrating circuit network(without op-amp) the output vo for a step input of V becomes \n'); +printf(' For a large Rc, vo ≈ (V*t)/R*C) * (1 - t/(2*R*C) .. eq(2)'); //Eq(2) +printf('\n\n'); +printf(' It can be seen that the output voltages of both circuits varies aproximately linearly with time(for large RC) and \n for either case, derivative(vo) = V/RC. \n However, the second term in both the expression represent deviation from the linearity. \n we see that op-amp integrator is more linear than the simple RC circuit by a factor of 1/(1-Av).\n'); -- cgit