From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

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 3681/CH4/EX4.11/Ex4_11.sce  |  20 ++++++++++++++++++++
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+// Calculating the heat conducted across the former from winding to core
+clc;
+disp('Example 4.11, Page No. = 4.17')
+// Given Data
+t = 2.5;// Thickness of former (in mm)
+t_air = 1;// Thickness of air space (in mm)
+lw = 150*250;// The inner dimentions of the former of field coil (in mm square)
+h = 200;// Winding height (in mm)
+s_former = 0.166;// Thermal conductivity of former (in W per meter per degree celsius)
+s_air = 0.05;// Thermal conductivity of air (in W per meter per degree celsius)
+T = 40;// Temperature rise (in degree celsius)
+// Calculation of the heat conducted across the former from winding to core
+S = 2*(150+250)*h*10^(-6);// Area of path of heat flow (in meter square)
+R_former = t*10^(-3)/(S*s_former);// Thermal resistance of former (in ohm)
+R_air = t_air*10^(-3)/(S*s_air);// Thermal resistance of former (in ohm)
+R0 = R_former+R_air;// Since R_former and R_air are in series. Total thermal resistance to heat flow (in ohm)
+Q_con = T/R0;// Heat conducted (in Watts)
+disp(Q_con,'Heat conducted across the former from winding to core (in Watts)=');
+//in book answers is 182.6 Watts.  The answers vary due to round off error
+
-- 
cgit