From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 3681/CH18/EX18.1/Ex18_1.sce | 38 ++++++++++++++++++++++++++++++++++++++
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(limited to '3681/CH18/EX18.1/Ex18_1.sce')

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+// Calculating the upper and lower limits of current during starting and resistance of each section
+clc;
+disp('Example 18.1, Page No. = 18.3')
+// Given Data
+// d.c. shunt motor
+P = 37;// Power rating (in kW)
+V = 250;// Voltage rating (in Volts)
+e = 0.84;// Full load efficiency
+rm = 0.2;// Armature circuit resistance (in ohm)
+ns = 8;// Number of studs
+// Maximum torque is 150% of full load torque
+// Calculation of the upper and lower limits of current during starting
+Ifl = P*10^(3)/(V*e);// Full load current (in Ampere)
+I1 = 1.5*Ifl;// Maximum current (in Ampere).  Since torque is proportional to current
+n = ns-1;// Number of sections
+alpha = (rm*I1/V)^(1/n);
+I2 = alpha*I1;// Lower limit of current (in Ampere)
+disp(I1,'Upper limit of current (Ampere) =');
+disp(I2,'Lower limit of current (Ampere) =');
+// Calculation of the resistance of each section
+R1 = V/I1;// Total resistance at starting (in ohm)
+r1 = (1-alpha)*R1;
+r2 = alpha*r1;
+r3 = alpha*r2;
+r4 = alpha*r3;
+r5 = alpha*r4;
+r6 = alpha*r5;
+r7 = alpha*r6;
+disp(R1,'Total resistance at starting (ohm) =');
+disp('Resistance of each section')
+disp(r1,'r1 (ohm) =');
+disp(r2,'r2 (ohm) =');
+disp(r3,'r3 (ohm) =');
+disp(r4,'r4 (ohm) =');
+disp(r5,'r5 (ohm) =');
+disp(r6,'r6 (ohm) =');
+disp(r7,'r7 (ohm) =');
+//in book answers are I1 = 264 ampere, I2 = 211 ampere, R1 = 0.947 ohm, r1 = 0.189 ohm,, r2 = 0.151 ohm, r3 = 0.121 ohm, r4 = 0.097 ohm, r5 = 0.077 ohm, r6 = 0.062 ohm, r7 = 0.050 ohm.    The answers vary due to round off error
-- 
cgit