From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

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 3542/CH9/EX9.4/Ex9_4.sce |  29 +++++++++++++++++++++++++++++
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 create mode 100644 3542/CH9/EX9.4/Ex9_4.sce

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+// Example no 9.4
+// To find a)the time duration of a bit b)the time duration of a slot c)the time duration of a frame d)how long must a user occupying single time slot wait between two successive transmission
+// Page no. 456
+
+clc;
+clear all;
+
+// Given data
+N=8;                                                        // Number of time slots in each frame
+Nb=156.25;                                                  // Number of in each time slot
+DR=270.833*10^3;                                            // Data rate of transmission in channel
+
+// a)To find the time duration of a bit 
+Tb=1/DR;                                                   // The time duration of a bit in sec
+
+// b)To find the time duration of a slot
+Tslot=Nb*Tb;                                              // The time duration of a slot
+
+// c)To find the time duration of a frame
+Tf=N*Tslot;                                               // The time duration of a frame
+
+//d) The waiting time between two successive transmission
+Tw=Tf;                                                   // The arrival time of new frame for its next transmission
+
+// Displaying the result in command window
+printf('\n The time duration of a bit = %0.3f microseconds',Tb*10^6);
+printf('\n The time duration of a slot = %0.3f ms',Tslot*10^3);
+printf('\n The time duration of a frame = %0.3f ms',Tf*10^3);
+printf('\n The arrival time of new frame for its next transmission = %0.3f ms',Tw*10^3);
-- 
cgit