From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

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 3542/CH4/EX4.8/Ex4_8.sce |  41 +++++++++++++++++++++++++++++++++++++++++
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+// Example no 4.8
+// To determine a)the loss due to knife-edge diffraction b)the heigth of obstacle required to induce 6dB diffraction loss
+// Page no. 133
+
+clc;
+clear;
+
+// Given data
+f=900*10^6;                                                  // Operating frequency in Hz
+c=3*10^8;                                                    // Speed of ligth in m/s
+hr=25;                                                       // Heigth of receiver in m
+ht=50;                                                       // Heigth of transmitter in m
+h=100;                                                      // Heigth of obstruction in m
+d1=10*10^3;                                                 // Distance between transmitter and obstruction in m
+d2=2*10^3;                                                  // Distance between receiver and obstruction in m
+
+// a)To determine the loss due to knife-edge diffraction
+lambda=c/f;                                                // Operating wavelength in m
+ht=ht-hr;                                                  // Hegth of transmitter after subtracting smallest heigth (hr)
+h=h-hr;                                                    // Heigth of obstruction after subtracting smallest heigth (hr)
+bet=atan((h-ht)/d1);                                       // From geometry of environment in rad
+gamm=atan(h/d2);                                           // From geometry of environment in rad
+alpha=bet+gamm;                                            // From geometry of environment in rad
+v=alpha*sqrt((2*d1*d2)/(lambda*(d1+d2)));                  // Fresnel diffraction parameter
+
+// the loss due to knife-edge diffraction
+Gd=-20*log10(0.225/v);                                     // Diffraction loss for v>2.4 in dB
+
+// Displaying the result in command window
+printf('\n The loss due to knife-edge diffraction = %0.1f dB',Gd);
+
+// b)To determine the heigth of obstacle required to induce 6dB diffraction loss
+Gd=6;                                                      // Diffraction loss in dB
+v=0;                                                       // Fresnel diffraction parameter from the plot of Knife-edge diffraction gain as a function of Fresnel diffraction parameter
+// v=0 is possible only if alpha=0. Therefore bet=-gamm
+// By considering this situation, the geometry of environment provides (h/d2)=(ht/(d1+d2))
+h=(ht*d2)/(d1+d2);                                         // the heigth of obstacle required to induce 6dB diffraction loss
+
+// Displaying the result in command window
+printf('\n The heigth of obstacle required to induce 6dB diffraction loss = %0.2f m',h);
+
-- 
cgit