From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 3516/CH17/EX17.5/Ex17_5.sce | 110 ++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 110 insertions(+) create mode 100644 3516/CH17/EX17.5/Ex17_5.sce (limited to '3516/CH17/EX17.5/Ex17_5.sce') diff --git a/3516/CH17/EX17.5/Ex17_5.sce b/3516/CH17/EX17.5/Ex17_5.sce new file mode 100644 index 000000000..5b5774818 --- /dev/null +++ b/3516/CH17/EX17.5/Ex17_5.sce @@ -0,0 +1,110 @@ +printf("\t example 17.5 \n"); +printf("\t approximate values are mentioned in the book \n"); +T1=85; +T2=120; +R=0.93; // R=(L/G), for 1500 gpm +printf("\t for 120percent of design \n"); +R1=1.2*R; +printf("\t R is : %.3f \n",R1); +H1=39.1; // at 87.2F +H2=H1+(R1*(T2-T1)); +printf("\t H2 is : %.1f Btu \n",H2); +// The area between the saturation line and the operating line represents the potential for heat transfer +// at T=87.2F +Hs=53.1; // from table in the solution +d1=(Hs-H1); +printf("\t difference is : %.1f \n",d1); +//at t=90 +Hs=56.7; // fig 17.12 +H=42; // fig 17.12 +d2=Hs-H; +printf("\t difference is : %.1f \n",d2); +d=(d1+d2)/(2); +printf("\t average of difference is : %.1f \n",d); +dT=(90-87.2); // F +nd1=(dT/d); +printf("\t nd1 is : %.3f \n",nd1); +// similarly calculating nd at each temperature and adding them will give you total nd value +nd=1.53; +printf("\t number of diffusing units : %.2f \n",nd); +printf("\t for 80 percent of design \n"); +R2=0.8*R; +printf("\t R is : %.3f \n",R2); +H1=39.1; // at 87.2F +H2=H1+(R2*(T2-T1)); +printf("\t H2 is : %.0f Btu \n",H2); +// The area between the saturation line and the operating line represents the potential for heat transfer +// at T=82.5F +Hs=47.2; // from table in the solution +d1=(Hs-H1); +printf("\t difference is : %.1f \n",d1); +//at t=85 +Hs=50; // fig 17.12 +H=40.8; // fig 17.12 +d2=Hs-H; +printf("\t difference is : %.1f \n",d2); +d=(d1+d2)/(2); +printf("\t average of difference is : %.1f \n",d); +dT=(85-82.5); // F +nd1=(dT/d); +printf("\t nd1 is : %.3f \n",nd1); +// similarly calculating nd at each temperature and adding them will give you total nd value +nd=1.92; +printf("\t number of diffusing units : %.2f \n",nd); +X=[1.115 0.93 0.74]; +Y=[1.53 1.70 1.92]; +plot2d(X,Y,style=3,rect=[0.7,1.4,1.3,2]); +xtitle("KxaV/L vs L/G","L/G","nd"); +printf("\t trial 1 \n"); +R3=1.1; +printf("\t R is : %.3f \n",R3); +H1=34.5; // at 87.2F +H2=H1+(R3*(T2-T1)); +printf("\t H2 is : %.0f Btu \n",H2); +// The area between the saturation line and the operating line represents the potential for heat transfer +// at T=85F +Hs=50; // from table in the solution +d1=(Hs-H1); +printf("\t difference is : %.1f \n",d1); +//at t=90 +Hs=56.7; // fig 17.12 +H=40; // fig 17.12 +d2=Hs-H; +printf("\t difference is : %.1f \n",d2); +d=(d1+d2)/(2); +printf("\t average of difference is : %.1f \n",d); +dT=(90-85); // F +nd1=(dT/d); +printf("\t nd1 is : %.3f \n",nd1); +// similarly calculating nd at each temperature and adding them will give you total nd value +nd=1.48; +printf("\t number of diffusing units : %.2f \n",nd); +R3=1.19; // from fig 17.14 +printf("\t L/G is : %.2f \n",R3); +printf("\t trial 2 \n"); +R4=1.2; +printf("\t R4 is : %.3f \n",R4); +H1=34.5; // at 87.2F +H2=H1+(R4*(T2-T1)); +printf("\t H2 is : %.1f Btu \n",H2); +// The area between the saturation line and the operating line represents the potential for heat transfer +// at T=85F +Hs=50; // from table in the solution +d1=(Hs-H1); +printf("\t difference is : %.1f \n",d1); +//at t=90 +Hs=56.7; // fig 17.12 +H=40.5; // fig 17.12 +d2=Hs-H; +printf("\t difference is : %.1f \n",d2); +d=(d1+d2)/(2); +printf("\t average of difference is : %.1f \n",d); +dT=(90-85); // F +nd1=(dT/d); +printf("\t nd1 is : %.3f \n",nd1); +// similarly calculating nd at each temperature and adding them will give you total nd value +nd=1.56; +printf("\t number of diffusing units : %.2f \n",nd); +R3=1.08; // from fig 17.14 +printf("\t L/G is : %.2f \n",R3); +// end -- cgit