From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 3516/CH15/EX15.5/Ex15_5.sce | 116 ++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 116 insertions(+)
 create mode 100644 3516/CH15/EX15.5/Ex15_5.sce

(limited to '3516/CH15/EX15.5/Ex15_5.sce')

diff --git a/3516/CH15/EX15.5/Ex15_5.sce b/3516/CH15/EX15.5/Ex15_5.sce
new file mode 100644
index 000000000..9607778b2
--- /dev/null
+++ b/3516/CH15/EX15.5/Ex15_5.sce
@@ -0,0 +1,116 @@
+printf("\t example 15.5\n");
+printf("\t approximate values are mentioned in the book \n");
+W=40800; // lb/hr
+w=4570; // lb/hr
+printf("\t 1.for heat balance \n");
+Ht1=241; // enthalpy of liquid at 228F, Btu/lb, fig 9
+Ht2=338; // enthalpy of vapourat 228F, Btu/lb, fig 9
+Q=(W*(Ht2-Ht1));
+printf("\t total heat required for butane is : %.2e Btu/hr \n",Q);
+l=868; // Btu/(lb), table 7
+Q=((w)*(l)); // Btu/hr
+printf("\t total heat required for steam is : %.2e Btu/hr \n",Q);
+delt=125; // delt=LMTD, isothermal boiling, eq 5.14
+// Tc and tc: Both streams are isuthermal
+printf("\t trail 1 \n");
+A1=((Q)/((12000))); // Q/A1 =12000, first trial should always be taken for the maximum allowable flux
+printf("\t A1 is : %.1e ft^2 \n",A1);
+a1=0.1963; // ft^2/lin ft
+L=16;
+N1=(A1/(L*a1)); // table 10
+printf("\t number of tubes are : %.0f \n",N1);
+N2=109; // assuming one tube passes, 13.25-in ID, from table 9
+A2=(N2*L*a1); // ft^2
+printf("\t total surface area is : %.0f ft^2 \n",A2);
+UD=((Q)/((A2)*(delt)));
+printf("\t correct design overall coefficient is : %.1f Btu/(hr)*(ft^2)*(F) \n",UD);
+// Assume 4: 1 recirculation ratio
+rowv=(58/(359*(688/492)*(14.7/290))); // eq 15.18
+printf("\t vapour density : %.2f lb/ft^3 \n",rowv);
+Vv=0.44; 
+Vl=0.0372; // fig 6
+W1=4*W;
+printf("\t weight flow of recirculated liquid : %.3e lb/hr \n",W1);
+VL=W1*Vl;
+VV=W*Vv;
+printf("\t volume of liquid : %.2e ft^3 \n",VL);
+printf("\t volume of vapour : %.3e ft^3 \n",VV);
+V=VL+VV;
+printf("\t total volume out of reboiler : %.3e ft^3 \n",V);
+vo=(V/(W1+W));
+printf("\t vo is : %.4f ft^3/lb \n",vo);
+Pl=((2.3*16)/(144*(vo-Vl)))*(log10(vo/Vl));
+printf("\t pressure leg : %.1f psi \n",Pl);
+printf("\t frictional resistance \n");
+Nt=109;
+n=1; // number of passes
+at1=0.302; // flow area,table 10, in^2
+at=((Nt*at1)/(144*n)); // total area,ft^2,from eq.7.48
+printf("\t flow area is : %.3f ft^2 \n",at);
+Gt=((W1+W)/(at)); // mass velocity,lb/(hr)*(ft^2)
+printf("\t mass velocity is : %.2e lb/(hr)*(ft^2) \n",Gt);
+mu1=0.242; // at 228F, fig 14,lb/(ft)*(hr)
+D=0.0517; // ft
+Ret=((D)*(Gt)/mu1); // reynolds number
+printf("\t reynolds number is : %.1e \n",Ret);
+f=0.000127; // using fig.26
+s=0.285;
+phyt=1;
+delPt=((f*(Gt^2)*(L)*(n))/(5.22*(10^10)*(D)*(s)*(phyt))); // using eq.7.45,psi
+printf("\t delPt is : %.2f psi \n",delPt);
+P=Pl+delPt;
+printf("\t total resisitance : %.2f psi \n",P);
+F=(16*0.43*62.5/144);
+printf("\t driving force : %.2f psi \n",F);
+// The resistances are greater than the hydrostatic head can provide; hence the recirculation ratio will be less than 4: 1
+printf("\t trial 2 \n"); // Assume 12'0" tubes and 4:1 recirculation ratio
+A1=((Q)/((12000))); // Q/A1 =12000, first trial should always be taken for the maximum allowable flux
+printf("\t A1 is : %.1e ft^2 \n",A1);
+a1=0.1963; // ft^2/lin ft
+L=12;
+N1=(A1/(L*a1)); // table 10
+printf("\t number of tubes are : %.0f \n",N1);
+N2=151; // assuming one tube passes, 15.25-in ID, from table 9
+A2=(N2*L*a1); // ft^2
+printf("\t total surface area is : %.0f ft^2 \n",A2);
+UD=((Q)/((A2)*(delt)));
+printf("\t correct design overall coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",UD);
+Pl=((2.3*12)/(144*(vo-Vl)))*(log10(vo/Vl));
+printf("\t pressure leg : %.1f psi \n",Pl);
+printf("\t frictional resistance \n");
+Nt=151;
+n=1; // number of passes
+at1=0.302; // flow area,table 10, in^2
+at=((Nt*at1)/(144*n)); // total area,ft^2,from eq.7.48
+printf("\t flow area is : %.3f ft^2 \n",at);
+Gt=((W1+W)/(at)); // mass velocity,lb/(hr)*(ft^2)
+printf("\t mass velocity is : %.2e lb/(hr)*(ft^2) \n",Gt);
+mu1=0.242; // at 228F, fig 14,lb/(ft)*(hr)
+D=0.0517; // ft
+Ret=((D)*(Gt)/mu1); // reynolds number
+printf("\t reynolds number is : %.2e \n",Ret);
+f=0.000135; // using fig.26
+s=0.285;
+phyt=1;
+delPt=((f*(Gt^2)*(12)*(n))/(5.22*(10^10)*(D)*(s)*(phyt))); // using eq.7.45,psi
+printf("\t delPt is : %.2f psi \n",delPt);
+P=Pl+delPt;
+printf("\t total resisitance : %.2f psi \n",P);
+F=(12*0.43*62.5/144);
+printf("\t driving force : %.2f psi \n",F);
+// Since the driving force is slightly greater than the resistances, a recirculation ratio better than 4:1 is assured.
+printf("\t hot fluid : shell side,steam \n");
+ho=1500; // condensing steam
+printf("\t cold fluid:inner tube side, butane \n");
+jH=330; // from fig.24
+Z=0.115; // Z=k*((c)*(mu1)/k)^(1/3), fig 16
+Hi=((jH)*(1/D)*(Z)); //, Hi=(hi/phyt)using eq.6.15d,Btu/(hr)*(ft^2)*(F)
+printf("\t individual heat transfer coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",Hi);
+Hio=((300)*(0.62/0.75)); //Hio=(hio/phyp), using eq.6.9
+printf("\t Correct Hio to the surface at the OD is : %.0f Btu/(hr)*(ft^2)*(F) \n",Hio);
+Uc=((Hio)*(ho)/(Hio+ho)); // clean overall coefficient,Btu/(hr)*(ft^2)*(F)
+printf("\t clean overall coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",Uc);
+UD=89;
+Rd=((Uc-UD)/((UD)*(Uc))); // (hr)*(ft^2)*(F)/Btu
+printf("\t actual Rd is : %.4f (hr)*(ft^2)*(F)/Btu \n",Rd);
+// end
-- 
cgit