From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 3472/CH41/EX41.1/Example41_1.sce | 30 ++++++++++++++++++++++++++++++ 1 file changed, 30 insertions(+) create mode 100644 3472/CH41/EX41.1/Example41_1.sce (limited to '3472/CH41/EX41.1/Example41_1.sce') diff --git a/3472/CH41/EX41.1/Example41_1.sce b/3472/CH41/EX41.1/Example41_1.sce new file mode 100644 index 000000000..ec06443ee --- /dev/null +++ b/3472/CH41/EX41.1/Example41_1.sce @@ -0,0 +1,30 @@ +// A Texbook on POWER SYSTEM ENGINEERING +// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar +// DHANPAT RAI & Co. +// SECOND EDITION + +// PART IV : UTILIZATION AND TRACTION +// CHAPTER 3: ELECTROLYTIC AND ELECTRO-METALLURGICAL PROCESSES + +// EXAMPLE : 3.1 : +// Page number 747-748 +clear ; clc ; close ; // Clear the work space and console + +// Given data +l = 20.0 // Length of shaft(cm) +d = 10.0 // Diameter of shaft(cm) +thick = 1.5 // Layer of nickel(mm) +J = 195.0 // Current density(A/sq.m) +n_I = 0.92 // Current efficiency +g = 8.9 // Specific gravity of nickel + +// Calculations +Wt = %pi*l*d*thick/10*g*10**-3 // Weight of nickel to be deposited(kg) +ece_nickel = 1.0954 // Electro-chemical equivalent of nickel(kg/1000 Ah) +Q_I = Wt*1000/(ece_nickel*n_I) // Quantity of electricity required(Ah) +time = Q_I/(%pi*l*d*10**-4*J) // Time taken(hours) + +// Results +disp("PART IV - EXAMPLE : 3.1 : SOLUTION :-") +printf("\nQuantity of electricity = %.f Ah", Q_I) +printf("\nTime taken for the process = %.f hours", time) -- cgit