From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 3472/CH40/EX40.6/Example40_6.sce | 36 ++++++++++++++++++++++++++++++++++++ 1 file changed, 36 insertions(+) create mode 100644 3472/CH40/EX40.6/Example40_6.sce (limited to '3472/CH40/EX40.6/Example40_6.sce') diff --git a/3472/CH40/EX40.6/Example40_6.sce b/3472/CH40/EX40.6/Example40_6.sce new file mode 100644 index 000000000..01c586c05 --- /dev/null +++ b/3472/CH40/EX40.6/Example40_6.sce @@ -0,0 +1,36 @@ +// A Texbook on POWER SYSTEM ENGINEERING +// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar +// DHANPAT RAI & Co. +// SECOND EDITION + +// PART IV : UTILIZATION AND TRACTION +// CHAPTER 2: HEATING AND WELDING + +// EXAMPLE : 2.6 : +// Page number 732 +clear ; clc ; close ; // Clear the work space and console + +// Given data +l = 10.0 // Length of material(cm) +b = 10.0 // Breadth of material(cm) +t = 3.0 // Thickness of material(cm) +f = 20.0*10**6 // Frequency(Hz) +P = 400.0 // Power absorbed(W) +e_r = 5.0 // Relative permittivity +PF = 0.05 // Power factor + +// Calculations +e_0 = 8.854*10**-12 // Absolute permittivity +A = l*b*10**-4 // Area(Sq.m) +C = e_0*e_r*A/(t/100) // Capacitace of parallel plate condenser(F) +X_c = 1.0/(2*%pi*f*C) // Reactance of condenser(ohm) +phi = acosd(PF) // Φ(°) +R = X_c*tand(phi) // Resistance of condenser(ohm) +V = (P*R)**0.5 // Voltage necessary for heating(V) +I_c = V/X_c // Current flowing in the material(A) + +// Results +disp("PART IV - EXAMPLE : 2.6 : SOLUTION :-") +printf("\nVoltage necessary for heating, V = %.f V", V) +printf("\nCurrent flowing in the material, I_c = %.2f A\n", I_c) +printf("\nNOTE: Changes in the obtained answer from that of textbook is due to more precision here & approximation in textbook") -- cgit