From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

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 3472/CH35/EX35.4/Example35_4.sce | 26 ++++++++++++++++++++++++++
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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 9: PROTECTION OF TRANSFORMERS
+
+// EXAMPLE : 9.4 :
+// Page number 636
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V_hv = 33.0           // HV side voltage of transformer(kV)
+V_lv = 6.6            // LV side voltage of transformer(kV)
+ratio_CT = 100.0/1    // CT ratio on LV side of transformer
+
+// Calculations
+CT_pri = 100.0              // Primary CT
+CT_sec = 1.0                // Secondary CT
+I_hv = V_lv/V_hv*CT_pri     // Line current on HV side(A)
+I_lv = CT_sec/3**0.5        // Line current on LV side(A)
+
+// Results
+disp("PART III - EXAMPLE : 9.4 : SOLUTION :-")
+printf("\nRatio of protective CTs on 33 kV side = %.f : %.f/√3 = %.f : %.f ", I_hv,CT_sec,3**0.5*I_hv,I_lv*3**0.5)
-- 
cgit