From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 3472/CH24/EX24.5/Example24_5.sce | 41 ++++++++++++++++++++++++++++++++++++++++ 1 file changed, 41 insertions(+) create mode 100644 3472/CH24/EX24.5/Example24_5.sce (limited to '3472/CH24/EX24.5/Example24_5.sce') diff --git a/3472/CH24/EX24.5/Example24_5.sce b/3472/CH24/EX24.5/Example24_5.sce new file mode 100644 index 000000000..6975ac3c5 --- /dev/null +++ b/3472/CH24/EX24.5/Example24_5.sce @@ -0,0 +1,41 @@ +// A Texbook on POWER SYSTEM ENGINEERING +// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar +// DHANPAT RAI & Co. +// SECOND EDITION + +// PART II : TRANSMISSION AND DISTRIBUTION +// CHAPTER 17: ELECTRIC POWER SUPPLY SYSTEMS + +// EXAMPLE : 17.5 : +// Page number 425 +clear ; clc ; close ; // Clear the work space and console + +// Given data +L = 60.0 // Line length(km) +P = 5.0 // Load(MW) +PF = 0.8 // Lagging power factor +V = 33.0*10**3 // Voltage(V) +n = 0.85 // Transmission efficiency +rho = 1.73*10**-8 // Specific resistance of copper(ohm-mt) +density = 8900.0 // Density(kg/mt^3) + +// Calculations +I = P*10**6/(3**0.5*V*PF) // Line current(A) +line_loss = (1-n)*P*1000/n // Line loss(kW) +line_loss_phase = line_loss/3.0 // Line loss/phase(kW) +R = line_loss_phase*1000/I**2 // Resistance/phase(ohm) +a = rho*L*1000/R // Area of cross section of conductor(m^2) +volume = 3.0*a*L*1000 // Volume of copper(m^3) +W_cu = volume*density // Weight of copper in 3-phase system(kg) +I_1 = P*10**6/V // Current in single phase system(A) +R_1 = line_loss*1000/(2*I_1**2) // Resistance in single phase system(ohm) +a_1 = rho*L*1000/R_1 // Area of cross section of conductor in single phase system(m^2) +volume_1 = 2.0*a_1*L*1000 // Volume of copper(m^3) +W_cu_1 = volume_1*density // Weight of copper in 1-phase system(kg) +reduction_cu = (W_cu-W_cu_1)/W_cu*100 // Reduction in copper(%) + +// Results +disp("PART II - EXAMPLE : 17.5 : SOLUTION :-") +printf("\nWeight of copper required for 3-phase 2-wire system = %.2e kg", W_cu) +printf("\nReduction of weight of copper possible = %.1f percent \n", reduction_cu) +printf("\nNOTE: ERROR: Calculation mistakes in the textbook solution") -- cgit