From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 3472/CH2/EX2.3/Example2_3.sce | 39 +++++++++++++++++++++++++++++++++++++++ 1 file changed, 39 insertions(+) create mode 100644 3472/CH2/EX2.3/Example2_3.sce (limited to '3472/CH2/EX2.3/Example2_3.sce') diff --git a/3472/CH2/EX2.3/Example2_3.sce b/3472/CH2/EX2.3/Example2_3.sce new file mode 100644 index 000000000..cd9d92df9 --- /dev/null +++ b/3472/CH2/EX2.3/Example2_3.sce @@ -0,0 +1,39 @@ +// A Texbook on POWER SYSTEM ENGINEERING +// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar +// DHANPAT RAI & Co. +// SECOND EDITION + +// PART I : GENERATION +// CHAPTER 2: THERMAL STATIONS + +// EXAMPLE : 2.3 : +// Page number 26 +clear ; clc ; close ; // Clear the work space and console + +//Given data +consumption = 0.5 // Coal consumption per kWh output(kg) +cal_value = 5000.0 // Calorific value(kcal/kg) +n_boiler = 0.8 // Boiler efficiency +n_elec = 0.9 // Electrical efficiency + +//Calculations +input_heat = consumption*cal_value // Heat input(kcal) +input_elec = input_heat/860.0 // Equivalent electrical energy(kWh). 1 kWh = 860 kcal +loss_boiler = input_elec*(1-n_boiler) // Boiler loss(kWh) +input_steam = input_elec-loss_boiler // Heat input to steam(kWh) +input_alter = 1/n_elec // Alternator input(kWh) +loss_alter = input_alter*(1-n_elec) // Alternate loss(kWh) +loss_turbine = input_steam-input_alter // Loss in turbine(kWh) +loss_total = loss_boiler+loss_alter+loss_turbine // Total loss(kWh) +output = 1.0 // Output(kWh) +Input = output+loss_total // Input(kWh) + +//Results +disp("PART I - EXAMPLE : 2.3 : SOLUTION :-") +printf("\nHeat Balance Sheet") +printf("\nLOSSES: Boiler loss = %.3f kWh", loss_boiler) +printf("\n Alternator loss = %.2f kWh", loss_alter) +printf("\n Turbine loss = %.3f kWh", loss_turbine) +printf("\n Total loss = %.2f kWh", loss_total) +printf("\nOUTPUT: %.1f kWh", output) +printf("\nINPUT: %.2f kWh\n", Input) -- cgit