From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 3308/CH10/EX10.1/Ex10_1.sce | 30 ++++++++++++++++++++++++++++++
 3308/CH10/EX10.1/Ex10_1.txt |  6 ++++++
 2 files changed, 36 insertions(+)
 create mode 100755 3308/CH10/EX10.1/Ex10_1.sce
 create mode 100755 3308/CH10/EX10.1/Ex10_1.txt

(limited to '3308/CH10')

diff --git a/3308/CH10/EX10.1/Ex10_1.sce b/3308/CH10/EX10.1/Ex10_1.sce
new file mode 100755
index 000000000..dcc72e4c6
--- /dev/null
+++ b/3308/CH10/EX10.1/Ex10_1.sce
@@ -0,0 +1,30 @@
+clc 
+// Given that
+//three metal piece being cast have the same volume but different shapes
+//shapes are sphere,cube,cylinder(height=diameter)
+
+// Sample Problem on page no. 252
+
+printf("\n #solidification time for various shapes# \n")
+
+//solidification time is inversely proportional to the square of surface area
+
+//for sphere
+r=(3/(4*3.14))^(1/3)//radius of the sphere from volume of sphere v=(4*3.14*r^3)/3
+A=4*3.14*((r)^2)
+time1=1/(A)^2
+printf("\n the solidification time for the sphere is %fC",time1)
+
+//for cube
+a=1//edge of the cube
+A=6*a^2
+time2=1/(A)^2
+printf("\n the solidification time for the cube is %fC",time2)
+
+//for cylinder
+//given height =diameter 
+//radius=2*height
+r=(1/(2*3.14))^(1/3)//radius of the cylinder from volume of the cylinder v=3.14*r^2*h
+A=(6*3.14*(r^2)) //area of the cylinder = (2*3.14*radius^2) + (2*3.14*radius*height)
+time3=1/(A)^2
+printf("\n the solidification time for the sphere is %fC",time3)
diff --git a/3308/CH10/EX10.1/Ex10_1.txt b/3308/CH10/EX10.1/Ex10_1.txt
new file mode 100755
index 000000000..edb84e7de
--- /dev/null
+++ b/3308/CH10/EX10.1/Ex10_1.txt
@@ -0,0 +1,6 @@
+ 
+ #solidification time for various shapes# 
+
+ the solidification time for the sphere is 0.042774C
+ the solidification time for the cube is 0.027778C
+ the solidification time for the sphere is 0.032643C
\ No newline at end of file
-- 
cgit