From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 2912/CH5/EX5.16/Ex5_16.sce | 23 +++++++++++++++++++++++
 1 file changed, 23 insertions(+)
 create mode 100755 2912/CH5/EX5.16/Ex5_16.sce

(limited to '2912/CH5/EX5.16')

diff --git a/2912/CH5/EX5.16/Ex5_16.sce b/2912/CH5/EX5.16/Ex5_16.sce
new file mode 100755
index 000000000..a47cf5a30
--- /dev/null
+++ b/2912/CH5/EX5.16/Ex5_16.sce
@@ -0,0 +1,23 @@
+//chapter 5
+//example 5.16
+//Calculate minimum uncertainty in the momentum and minimum kinetic energy of proton
+//page 108-109
+clear;
+clc;
+//given
+dx=5E-15; // in m (radius of nucleus or uncertainty in the position)
+h=6.6E-34; // in J-s (Planck's constant)
+m=1.67E-27; // in Kg (mass of proton)
+pi=3.14; // value of pi used in the solution
+e=1.6E-19; // in C (charge of electron)
+//calculate
+// Since dx*dp=h/4*pi  (uncertainty relation)
+dp=h/(4*pi*dx); // calculation of uncertainty in the momentum
+printf('\nThe minimum uncertainty in the momentum of proton is\tdp=%1.2E Kg-m/s',dp);
+p=dp; // minimum value of momentum to calculate mimimum kinetic energy
+K=p^2/(2*m); // calculation of minimum kinetic energy of proton
+printf('\nThe minimum kinetic energy of proton is\tK=%1.1E J',K);
+K=K/e; //changing unit from J to eV
+printf('\n\t\t\t\t\t=%1.1E eV',K);
+K=K/1E6; // changing unit from eV to MeV
+printf('\n\t\t\t\t\t=%.1f MeV',K);
-- 
cgit