From f35ea80659b6a49d1bb2ce1d7d002583f3f40947 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:38:01 +0530
Subject: updated the code

---
 278/CH14/EX14.6/ex_14_6.sce | 40 ++++++++++++++++++++--------------------
 1 file changed, 20 insertions(+), 20 deletions(-)

(limited to '278/CH14/EX14.6')

diff --git a/278/CH14/EX14.6/ex_14_6.sce b/278/CH14/EX14.6/ex_14_6.sce
index f9a6d088b..c51a0736e 100755
--- a/278/CH14/EX14.6/ex_14_6.sce
+++ b/278/CH14/EX14.6/ex_14_6.sce
@@ -1,20 +1,20 @@
-//determine dia of the shaft
-clc
-//solution
-//given
-P=7.5*10^3//W
-N=300//rpm
-D=150//mm
-L=200//mm
-t=45//N/mm^2
-a=(%pi/180)*20//rad
-//reff fig 14.2
-T=P*60000/(2*%pi*200)//N-mm
-Ft=2*T/D//N
-W=Ft/(cos(a))//N
-M=W*L/4//N-mm
-//let d be dia
-Te=sqrt(T^2 + M^2)//N-mm
-//Te=(%pi/16)*t*d^3
-d=(Te/8.84)^(1/3)//mm
-printf("the dia of shaft is,%f mm",d)
+
+clc
+//solution
+//given
+P=7.5*10^3//W
+N=300//rpm
+D=150//mm
+L=200//mm
+t=45//N/mm^2
+a=(%pi/180)*20//rad
+//reff fig 14.2
+T=P*60000/(2*%pi*200)//N-mm
+Ft=2*T/D//N
+W=Ft/(cos(a))//N
+M=W*L/4//N-mm
+//let d be dia
+Te=sqrt(T^2 + M^2)//N-mm
+//Te=(%pi/16)*t*d^3
+d=(Te/8.84)^(1/3)//mm
+printf("the dia of shaft is,%f mm",d)
-- 
cgit