From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 2774/CH8/EX8.10/Ex8_10.sce | 39 +++++++++++++++++++++++++++++++++++++++
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 create mode 100755 2774/CH8/EX8.10/Ex8_10.sce

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+clc
+//solution
+// initialization of variables
+mdotw3=10000 // mass flow rate of water entering in cooling tower in kg/min
+Tw1=40+273 // temperature of water entering cooling tower in kelvin
+Ta1=20+273 // temperature of air entering cooling tower in kelvin
+phi1=0.5// relative humidity of entering air
+Tw2=25+273 // temperature of water leaving cooling tower in kelvin
+Ta2=32+273 // temperature of air leaving cooling tower in kelvin
+phi2=0.98 // relative humidity of leaving air
+// from psychrometric chart
+h1=37// specific enthalpy of air @ 20*C DBT and 50% humidity
+w1=0.0073 // specific humidity of air @ 20*C DBT and 50% humidity
+h2=110// specific enthalpy of air @ 32*C DBT and 98% humidity
+w2=0.030 // specific humidity of air @ 32*C DBT and 98% humidity
+
+h3=167.5 // specific enthalpy of water from steam table at 40 degree celsius
+h4=104.9 // specific enthalpy of water from steam table at 25 degree celsius
+
+mdota=(mdotw3*(h4-h3))/(h1-h2+(w2-w1)*h4) // by energy balance
+
+
+v1=0.84 // specific volume of air entering tower from psychrometric chart
+
+Qf=mdota*v1 // volume flow rate in m^3/min
+printf("The volume flow rate of air into the cooling tower is %i m^3/min \n",Qf)
+
+mdot4=mdotw3-(w2-w1)*mdota // by mass balance
+printf("The mass flow rate of water that leaves the cooling tower is %i kg/min",mdot4) 
+// The answers is slightly different in textbook due to approximations in calculations while in scilab solution is precise
+
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-- 
cgit