From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 2762/CH2/EX2.7.5/2_7_5.sce | 32 ++++++++++++++++++++++++++++++++ 1 file changed, 32 insertions(+) create mode 100755 2762/CH2/EX2.7.5/2_7_5.sce (limited to '2762/CH2/EX2.7.5/2_7_5.sce') diff --git a/2762/CH2/EX2.7.5/2_7_5.sce b/2762/CH2/EX2.7.5/2_7_5.sce new file mode 100755 index 000000000..ea4cf47e0 --- /dev/null +++ b/2762/CH2/EX2.7.5/2_7_5.sce @@ -0,0 +1,32 @@ +//Transport Processes and Seperation Process Principles +//Chapter 2 +//Example 2.7-5 +//Principles of Momentum Transfer and Overall Balances +//given data +//cgs units +V=69.1;//volumetric flow rate in gallon/min +fr1=V*(1/60)*(1/7.481);//converting flow rate in ft3/s +A1=0.0233;//cross section area in ft2 of the pipe +v2=fr1/A1;//vel in ft/s +v1=0;//since the tank is very large +p1=1;//atm pressure +p2=p1; +gc=32.174; +z1=0;//datum +g=32.174; +z2=50;//length of discharge line in ft +rho=114.8;//density of liq soln +F1=10;//friction loss in ft-lb force/lb mass +Ws=(z1*(g/gc))-(z2*(g/gc))+(v1*v1/(2*gc))-(v2*v2/(2*gc))+((p1-p2)/rho)-F1;//shaft work calculated by mechanical energy equation +n=0.65;//efficiency +Wp=(-Ws/n); +m=fr1*rho;//mass flow rate in lbm/s +P=m*Wp*(1/550);//pump horsepower +A2=0.05134;//area of cross section +v3=fr1/A2; +v4=v2; +F2=0;//friction losses in the second pipe is negligible +Pdbyrho=(v3*v3/(2*gc))-(v4*v4/(2*gc))-Ws-F2; +Pdiff=Pdbyrho*(rho/144);//pressure diff in lb force/in2 +mprintf("pressure developed by pump = %f psia",Pdiff) +mprintf(" pump horsepower= %f hp",P) -- cgit