From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 2642/CH3/EX3.16/Ex3_16.sce | 33 +++++++++++++++++++++++++++++++++ 1 file changed, 33 insertions(+) create mode 100755 2642/CH3/EX3.16/Ex3_16.sce (limited to '2642/CH3/EX3.16') diff --git a/2642/CH3/EX3.16/Ex3_16.sce b/2642/CH3/EX3.16/Ex3_16.sce new file mode 100755 index 000000000..9ab6e7a35 --- /dev/null +++ b/2642/CH3/EX3.16/Ex3_16.sce @@ -0,0 +1,33 @@ +// FUNDAMENTALS OF ELECTICAL MACHINES +// M.A.SALAM +// NAROSA PUBLISHING HOUSE +// SECOND EDITION + +// Chapter 3 : TRANSFORMER AND PER UNIT SYSTEM +// Example : 3.16 + + +clc;clear; // clears the console and command history + +// Given data +V_b = 220 // voltage in V +f = 50 // frequency in Hz +S_b = 600 // power ratings +R = 3 // resistance in ohm +X_L = 5 // inducatnce in ohm +Z = R+X_L // impedance + +// caclulations +I_b = S_b/V_b // base value of current in A +Z_b = V_b^2/S_b // base value of impedance in ohm +R_pu = R/Z_b // per unit value of resistance in ohm +X_Lpu = X_L/Z_b // per unit value of impedance in ohm +Z_pu = abs(Z)/Z_b // per unit of value of impedance in ohm +Z_pu = R_pu+%i*X_Lpu // per unit of value of impedance in ohm NOTE:alternative method + +// display the result +disp("Example 3.16 solution"); +printf(" \n Per unit value of resistance \n R_pu = %.3f ohm \n", R_pu); +printf(" \n Per unit value of impedance \n X_Lpu = %.3f ohm \n", X_Lpu); +printf(" \n Per unit of value of impedance \n Z_pu = %.3f<%.f \n", abs(Z_pu),atand(imag(Z_pu),real(Z_pu))); + -- cgit