From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 2642/CH11/EX11.1/Ex11_1.sce | 34 ++++++++++++++++++++++++++++++++++
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diff --git a/2642/CH11/EX11.1/Ex11_1.sce b/2642/CH11/EX11.1/Ex11_1.sce
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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 11 : SINGLE-PHASE MOTORS
+// Example : 11.1
+
+clc;clear; // clears the console and command history 
+
+// Given data
+V = 220            // supply voltage in V
+P = 4              // number of poles
+f = 50             // frequency in Hz
+N_l = 1450         // speed in rpm
+P_tloss = 2000     // total power loss in W
+R_2 = 10           // rotor resistance at standstill in ohm
+
+// caclulations
+N_s = 120*f/P       // synchronous speed in rpm
+s_f = (N_s-N_l)/N_s // slip due to forward field
+s_b = 2-s_f         // slip due to backward field
+R_f = R_2/s_f       // effective rotor resistance due to forward slip in ohm
+R_b = R_2/(2-s_f)   // effective rotor resistance due to backward slip in ohm
+
+// display the result  
+disp("Example 11.1 solution"); 
+printf(" \n Slip due to forward field \n s_f = %.2f \n", s_f );
+printf(" \n Slip due to backward field \n s_b = %.2f \n", s_b );
+printf(" \n Effective rotor resistance due to forward slip \n R_f = %.2f ohm \n", R_f );
+printf(" \n Effective rotor resistance due to backward slip \n R_b = %.2f ohm \n", R_b );
+
+printf(" \n NOTE : for caclulating R_f, s_f is taken as 0.033333 so we got R_f=300");
+
-- 
cgit