From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 1 : REVIEW OF ELECRTIC CIRCUITS  
+// Example : 1.3 
+
+clc;clear; // clears the console and command history 
+// Given data 
+R1 = 5  // resistance in ohm 
+R2 = 4  // resistance in ohm 
+R3 = 9  // resistance in ohm 
+R4 = 6  // resistance in ohm 
+V1 = 10 // voltage in V
+V2 = 6  // voltage in V
+
+
+// caclulations 
+// Remove R3 and find R_th by short circuiting  V1 and V2 than R1 and R4  wiil be in parallel 
+R = (R1*R4)/(R1+R4)   // equivalent resistance in ohm
+// R is connected in series with R2 
+R_th = R2+R           // Thevenin's resistance in ohm
+I = 4/11              // current in the figure applying KVL in A
+V_th = (6*0.36)+6     // voltage in V
+I_9 = V_th/(R_th+R3) // current through R3 in A
+
+
+// display the result 
+disp("Example 1.3 solution");
+printf(" \n Current through 9Ω \n I_9Ω = %.2f A ", I_9); 
-- 
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