From f35ea80659b6a49d1bb2ce1d7d002583f3f40947 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:38:01 +0530
Subject: updated the code

---
 249/CH5/EX5.2/5_02.sce | 85 +++++++++++++++++++++++++++++---------------------
 1 file changed, 49 insertions(+), 36 deletions(-)

(limited to '249/CH5/EX5.2/5_02.sce')

diff --git a/249/CH5/EX5.2/5_02.sce b/249/CH5/EX5.2/5_02.sce
index 0f9eb6da2..be0f4e030 100755
--- a/249/CH5/EX5.2/5_02.sce
+++ b/249/CH5/EX5.2/5_02.sce
@@ -1,37 +1,50 @@
-clear
-clc
-//Given
-//Volumetric flow rates(litre/hr)
-vo=[10;3;1.2;0.5];
-//Concentrations (millimol/litre)
-CA=[85.7;66.7;50;33.4];
-CAo=100;
-//Volume(litre)
-V=0.1;
-//For the stoichiometry 2A-->R
-//Expansion factor is
-e=(1-2)/2;
-//Initialization
-XA=zeros(4,1);
-rA=zeros(4,1);
-//Relation between concentration and conversion
-for i=1:4
-XA(i)=(1-CA(i)/CAo)/(1+e*CA(i)/CAo);
-//Rate of reaction is given by
-rA(i)=vo(i)*CAo*XA(i)/V;
-//Testing nth order kinetics
-//-rA=k*CA^n
-//log(-rA)=logk+nlog(CA)
-m(i)=log10(CA(i));
-n(i)=log10(rA(i));
-end
-//For nth order plot between n & m should give a straight line
-plot(m,n)
-coefs=regress(m,n);
-printf("Intercept of the graph is %f\n",coefs(1))
-printf("Slope of the graph is %f\n",coefs(2))
-k=10^coefs(1)
-n=coefs(2)
-printf("\n Taking n=2,rate of equation(millimol/litre.hr) is %f",k)
-printf("CA^2 \n")
+clear
+clc
+function [coefs]=regress(x,y)
+coefs=[]
+  if (type(x) <> 1)|(type(y)<>1) then error(msprintf(gettext("%s: Wrong type for input arguments: Numerical expected.\n"),"regress")), end
+  lx=length(x)
+  if lx<>length(y) then error(msprintf(gettext("%s: Wrong size for both input arguments: same size expected.\n"),"regress")), end
+  if lx==0 then error(msprintf(gettext("%s: Wrong size for input argument #%d: Must be > %d.\n"),"regress", 1, 0)), end
+  x=matrix(x,lx,1)
+  y=matrix(y,lx,1)
+  xbar=sum(x)/lx
+  ybar=sum(y)/lx
+  coefs(2)=sum((x-xbar).*(y-ybar))/sum((x-xbar).^2)
+  coefs(1)=ybar-coefs(2)*xbar
+endfunction
+//Given
+//Volumetric flow rates(litre/hr)
+vo=[10;3;1.2;0.5];
+//Concentrations (millimol/litre)
+CA=[85.7;66.7;50;33.4];
+CAo=100;
+//Volume(litre)
+V=0.1;
+//For the stoichiometry 2A--&gt;R
+//Expansion factor is
+e=(1-2)/2;
+//Initialization
+XA=zeros(4,1);
+rA=zeros(4,1);
+//Relation between concentration and conversion
+for i=1:4
+XA(i)=(1-CA(i)/CAo)/(1+e*CA(i)/CAo);
+//Rate of reaction is given by
+rA(i)=vo(i)*CAo*XA(i)/V;
+//Testing nth order kinetics
+//-rA=k*CA^n
+//log(-rA)=logk+nlog(CA)
+m(i)=log10(CA(i));
+n(i)=log10(rA(i));
+end
+//For nth order plot between n &amp; m should give a straight line
+plot(m,n)
+coefs=regress(m,n);
+printf("Intercept of the graph is %f\n",coefs(1))
+printf("Slope of the graph is %f\n",coefs(2))
+k=10^coefs(1)
+n=coefs(2)
+printf("\n Taking n=2,rate of equation(millimol/litre.hr) is %f",k)
+printf("CA^2 \n")
 disp('The sol slightly differ from that given in book because regress fn is used to calculate the slope')
\ No newline at end of file
-- 
cgit