From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 2471/CH10/EX10.1/Ex10_1.sce | 30 ++++++++++++++++++++++++++++++
 1 file changed, 30 insertions(+)
 create mode 100755 2471/CH10/EX10.1/Ex10_1.sce

(limited to '2471/CH10/EX10.1')

diff --git a/2471/CH10/EX10.1/Ex10_1.sce b/2471/CH10/EX10.1/Ex10_1.sce
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+clear ;
+clc;
+// Example 10.1
+printf('Example 10.1\n\n');
+printf('Page No. 293\n\n');
+
+// given
+m = 1;// mass flow rate of initial air mixture in kg/s
+T = 23.5;// Initial temperature in degree celcius
+m1 = 0.6;// Percentage of fresh air mixture
+T1 = 5;// Dry Bulb Temperature of  fresh air in degree celcius
+w1 = 0.005;// Humidity  of fresh air at temperature T1 in kg/kg
+m2 = 0.4;// Percentage of recirculated air mixture
+T2 = 25;// Dry Bulb Temperature of recirculated air in degree celcius
+w2 = 0.015;// Humidity  of recirculated air at temperature T2 in kg/kg
+
+//In air conditioning => m1*w1 + m2*w2 = m*w
+w = (m1*w1 + m2*w2)/m;// in kg/kgs
+printf('The humidity of the air mixture  is %.3f kg/kg \n',w)
+
+//The specific enthalpy in J/kg can be calculated by the formula => h = (1.005*10^3*T) +(w*((2.50*10^6)+(1.86*10^3*T))); where the T is the temperature and w is the humidity at temperature T
+h_f = (1.005*10^3*T1) +(w1*((2.50*10^6)+(1.86*10^3*T1)));// Specific enthalpy of fresh air in J/kg
+h_r = (1.005*10^3*T2) +(w2*((2.50*10^6)+(1.86*10^3*T2)));// Specific enthalpy of recirculated  air in J/kg
+h_m = (1.005*10^3*T) +(w*((2.50*10^6)+(1.86*10^3*T)));// Specific enthalpy of  final air mixture in J/kg
+
+h_t = (m1*h_f) + (m2*h_r);// Total enthalpy of initial air mixturein J/kg
+Q = m*(h_m - h_t);// in Watts
+printf('The load on the heater is% .3f W',Q)
+// Deviation in answer due to direct substitution and some approximation in answer in book
+
-- 
cgit