From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 2417/CH5/EX5.3/Ex5_3.sce | 38 ++++++++++++++++++++++++++++++++++++++ 1 file changed, 38 insertions(+) create mode 100755 2417/CH5/EX5.3/Ex5_3.sce (limited to '2417/CH5/EX5.3') diff --git a/2417/CH5/EX5.3/Ex5_3.sce b/2417/CH5/EX5.3/Ex5_3.sce new file mode 100755 index 000000000..a87476923 --- /dev/null +++ b/2417/CH5/EX5.3/Ex5_3.sce @@ -0,0 +1,38 @@ +//scilab 5.4.1 +clear; +clc; +printf("\t\t\tProblem Number 5.3\n\n\n"); +// Chapter 5 : Properties Of Liquids And Gases +// Problem 5.3 (page no. 188) +// Solution + +//The necessary interpolations are best done in tabular forms as shown: +// p hg +// 115 1190.4 table 2 +// 118 1190.8 (hg)118=1190.8 +// 120 1191.1 +hg=1190.4+(3/5)*(1191.1-1190.4); //Btu/lbm //enthaply +printf("The enthalpy of saturated steam at 118 psia is %f Btu/lbm\n",hg); + +// p vg +// 115 3.884 table 2 +// 118 3.792 (vg)118=3.790 +// 120 3.730 +vg=3.884-(3/5)*(3.884-3.730); //ft^3/lbm //specific volume +printf("The specific volume of saturated steam at 118 psia is %f ft^3/lbm\n",vg); + +// p sg +// 115 1.5921 table 2 +// 118 1.5900 (sg)118=1.5900 +// 120 1.5886 +sg=1.5921-(3/5)*(1.5921-1.5886); //entropy +printf("The entropy of saturated steam at 118 psia is %f\n",sg); + +// p ug +// 115 1107.7 table 2 +// 118 1108.06 (ug)118=1180.1 +// 120 1108.3 +ug=1107.7-(3/5)*(1108.3-1107.7); //internal energy +printf("The internal energy of saturated steam at 118 psia is %f\n",ug); +//The interpolation process that was done in tabular form for this problem can also be demonstated by refering to figure 5.8 for the specific volume.It will be +//seen that the results of this problem and the tabulated values are essentially in exact agreement and that linear interpolation is satisfactory in these tables. -- cgit