From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 2090/CH10/EX10.1/Chapter10_example1.sce | 31 +++++++++++++++++++++++++++++++
 2090/CH10/EX10.2/Chapter10_example2.sce | 25 +++++++++++++++++++++++++
 2090/CH10/EX10.3/Chapter10_example3.sce | 18 ++++++++++++++++++
 2090/CH10/EX10.4/Chapter10_example4.sce | 20 ++++++++++++++++++++
 2090/CH10/EX10.5/Chapter10_example5.sce | 22 ++++++++++++++++++++++
 2090/CH10/EX10.6/Chapter10_example6.sce | 29 +++++++++++++++++++++++++++++
 2090/CH10/EX10.7/Chapter10_example7.sce | 29 +++++++++++++++++++++++++++++
 7 files changed, 174 insertions(+)
 create mode 100755 2090/CH10/EX10.1/Chapter10_example1.sce
 create mode 100755 2090/CH10/EX10.2/Chapter10_example2.sce
 create mode 100755 2090/CH10/EX10.3/Chapter10_example3.sce
 create mode 100755 2090/CH10/EX10.4/Chapter10_example4.sce
 create mode 100755 2090/CH10/EX10.5/Chapter10_example5.sce
 create mode 100755 2090/CH10/EX10.6/Chapter10_example6.sce
 create mode 100755 2090/CH10/EX10.7/Chapter10_example7.sce

(limited to '2090/CH10')

diff --git a/2090/CH10/EX10.1/Chapter10_example1.sce b/2090/CH10/EX10.1/Chapter10_example1.sce
new file mode 100755
index 000000000..891ce3361
--- /dev/null
+++ b/2090/CH10/EX10.1/Chapter10_example1.sce
@@ -0,0 +1,31 @@
+clc
+clear
+//Input data
+bsfc=0.3;//The brake specific fuel consumption in kg/kWh
+bp=250;//The brake power in kW
+N=1500;//Number of cycles per min in rpm
+CA=15;//Crank angle in degrees
+pi1=30;//The pressure of air in the cylinder at the beginning of the injection in bar
+pi2=60;//The pressure of air in the cylinder at the end of the injection in bar
+pf1=220;//The fuel injection pressure at the beginning in bar
+pf2=550;//The fuel injection pressure at the end in bar
+Cd=0.65;//The coefficient of discharge for the injector 
+df=850;//The density of the fuel in kg/m^3
+p1=1.013;//The atmospheric pressure in bar
+n=4;//The number of orifices used in the nozzle
+x=6;//Number of cylinders
+pi=3.141;//The mathematical constant of pi
+
+//Calculations
+mf=bsfc*bp/60;//The mass flow rate of fuel in kg/min
+F=(mf/(N/2))*(1/x);//Fuel injected per cycle per cylinder in kg
+s=(CA/360)/(N/60);//Duration of injection in s
+mf1=F/s;//Mass of fuel injected per second
+p1=pf1-pi1;//Pressure difference at the beginning in bar
+p2=pf2-pi2;//Pressure difference at the end in bar
+pa=(p1+p2)/2;//Average pressure difference in bar
+Af=[mf1/(Cd*(2*df*pa*10^5)^(1/2))]*10^6;//Area of cross section of the nozzle in mm^2
+do=[(Af/n)*(4/pi)]^(1/2);//The diameter of the orifice in mm
+
+//Output
+printf('The nozzle area required per injection = %3.3f mm^2 \n The diameter of the orifice = %3.2f mm ',Af,do)
diff --git a/2090/CH10/EX10.2/Chapter10_example2.sce b/2090/CH10/EX10.2/Chapter10_example2.sce
new file mode 100755
index 000000000..9cbb644c6
--- /dev/null
+++ b/2090/CH10/EX10.2/Chapter10_example2.sce
@@ -0,0 +1,25 @@
+clc
+clear
+//Input data
+bp=30;//The brake power of the engine in kW
+N=3000;//The engine speed in rpm 
+bsfc=0.28;//The brake specific fuel consumption in kg/kWh 
+API=35;//The API
+p2=160;//The pressure at which fuel is injected in bar
+CA=28;//The crank angle in degrees
+p1=35;//The pressure in the combustion chamber in bar
+Cv=0.92;//The coefficient of velocity 
+pi=3.141;//The mathematical constant of pi
+
+//Calculations
+S=141.5/(131.5+API);//Specific gravity
+df=S*1000;//The density of the fuel in kg/m^3
+D=(CA/360)/(N/60);//Duration of injection in s
+F=(bsfc*bp)/((N/2)*60);//Fuel consumption per cycle in kg
+mf=F/D;//Mass flow rate of fuel in kg/s
+Cf=Cv*((2*(p2-p1)*10^5)/df)^(1/2);//Velocity of injection of the fuel in m/s
+Af=[mf/(df*Cf)]*10^6;//Area of the fuel orifice in mm^2
+d=(4*Af/pi)^(1/2);//The diameter of the orifice in mm
+
+//Output
+printf('The velocity of injection of the fuel = %3.1f m/s \n The diameter of the fuel orifice = %3.3f mm ',Cf,d)
diff --git a/2090/CH10/EX10.3/Chapter10_example3.sce b/2090/CH10/EX10.3/Chapter10_example3.sce
new file mode 100755
index 000000000..c513826a0
--- /dev/null
+++ b/2090/CH10/EX10.3/Chapter10_example3.sce
@@ -0,0 +1,18 @@
+clc
+clear
+//Input data
+d=0.8*10^-3;//The diameter of an orifice in m
+A=1.65*10^-6;//The cross sectional area in m^2
+Cd=0.9;//The discharge coefficient of the orifice 
+Cp=0.85;//The coefficient of the passage
+p1=170;//The injection pressure in bar
+p2=25;//The compression pressure of the discharge in bar
+df=850;//The density of the fuel in kg/m^3
+
+//Calculations
+Q=[(145/(22.931*10^9))^(1/2)]*10^6;//Adding two equations and solving then the discharge in cm^3/s
+p=170-(2.161*10^9*(Q/10^6)^2);//Pressure immediately formed before the orifice in bar
+Cf=Cd*((2*(p-p2)*10^5)/df)^(1/2);//The velocity of fuel flow through the orifice in m/s
+
+//Output
+printf('The discharge of fuel through the injector = %3.1f cm^2/s \n The jet velocity through the orifice = %3.1f m/s ',Q,Cf)
diff --git a/2090/CH10/EX10.4/Chapter10_example4.sce b/2090/CH10/EX10.4/Chapter10_example4.sce
new file mode 100755
index 000000000..8b93d9cdc
--- /dev/null
+++ b/2090/CH10/EX10.4/Chapter10_example4.sce
@@ -0,0 +1,20 @@
+clc
+clear
+//Input data
+s=20;//Spray penetration in cm
+t1=15.7;//The spray penetration of 20 cm in ms
+pi1=150;//The injection pressure in bar
+pi2=450;//The injection pressure to be used in bar
+p2=15;//The combustion chamber pressure in bar
+d1=0.34;//The diameter of the orifice in mm
+s1=20;//The penetration for an orifice in cm
+d2=0.17;//If the diameter of the orifice in cm
+t11=12;//The spray penetration in ms
+
+//Calculations
+t2=(t1*(pi1-p2)^(1/2))/(pi2-p2)^(1/2);//The time required for the spray to penetrate in ms
+s2=d2*(s1/d1);//The penetration of the orifice in cm
+t21=t11*(d2/d1);//The time required for the spray to penetrate in ms
+
+//Output
+printf('(a) The time required for the spray to penetrate = %3.2f ms \n (b) The spray penetration of the orifice = %3.0f cm \n The time required for the spray to penetrate = %3.0f ms ',t2,s2,t21)
diff --git a/2090/CH10/EX10.5/Chapter10_example5.sce b/2090/CH10/EX10.5/Chapter10_example5.sce
new file mode 100755
index 000000000..bb758028b
--- /dev/null
+++ b/2090/CH10/EX10.5/Chapter10_example5.sce
@@ -0,0 +1,22 @@
+clc
+clear
+//Input data
+v=6.5;//The volume of fuel in the barrel in cc
+d=0.3;//The dimeter of fuel pipe line in cm
+l=65;//The length of the fuel pipe line in cm 
+vi=2.5;//The volume of fuel in the injection valve in cc
+K=78.5*10^-6;//The coefficient of compressibility of the oil per bar
+p1=1;//The atmospheric pressure in bar
+p2=180;//The pressure due to pump in bar
+v3=0.1;//The pump displacement necessary for the fuel in cc
+e=0.75;//The effective stroke of the plunger in cm
+pi=3.141;//Mathematical constant of pi
+
+//Calculations
+V1=v+((pi*d^2)/4)*l+vi;//The total initial volume in cc
+V=K*V1*(p2-p1);//Change in volume due to compression in cc
+T=(V)+v3;//Total displacement of the plunger in cc
+L=T*(4/pi)*(1/(e^2));//Effective stroke of the plunger in cm
+
+//Output
+printf('(a) The total displacement of the plunger = %3.3f cc \n (b) The effective stroke of the plunger = %3.3f cm',T,L)
diff --git a/2090/CH10/EX10.6/Chapter10_example6.sce b/2090/CH10/EX10.6/Chapter10_example6.sce
new file mode 100755
index 000000000..5c575db5f
--- /dev/null
+++ b/2090/CH10/EX10.6/Chapter10_example6.sce
@@ -0,0 +1,29 @@
+clc
+clear
+//Input data
+n=4;//Number of cylinders 
+N=2500;//The engine speed in rpm 
+P=90;//The power produced by the engine in kW
+bsfc=0.28;//The brake specific fuel consumption in kg/kWh
+v=3.5;//The volume of fuel in the barrel in cc
+vp=2.5;//Volume of fuel in the pipe line in cc
+vi=2;//The fuel inside the injector in cc
+p1=280;//The average injection pressure in bar
+p2=30;//The compression pressure of air during injection in bar
+df=850;//The density of the fuel in kg/m^3
+K=80*10^-6;//The coefficient of compressibility of fuel per bar
+pi=1;//The pressure with which fuel enter into the barrel in bar
+
+//Calculations
+F=(bsfc*P)/((N/2)*60);//Fuel consumption per cycle in kg
+F1=F/n;//Fuel consumption per cylinder in kg/cycle
+Vf=[F1/df]*10^6;//Volume of fuel injected per cylinder per cycle in cm^3
+V1=v+vp+vi;//Total initial volume in cc
+V=K*V1*(p1-pi);//Change in volume due to compression in cc
+Vp=Vf+V;//Volume displaced by plunger in cc
+W=[(1/2)*(p1-pi)*10^5*V*10^-6]+[(p1-p2)*10^5*Vf*10^-6];//Pump work per cycle in J
+P1=(W*N)/(2*60*1000);//Power lost per cylinder in kW
+P2=P1*4;//Total power lost for pumping the fuel in kW
+
+//Output 
+printf('The displacement volume of one plunger per cycle = %3.4f cc \n Total power lost for pumping the fuel = %3.3f kW',Vp,P2)
diff --git a/2090/CH10/EX10.7/Chapter10_example7.sce b/2090/CH10/EX10.7/Chapter10_example7.sce
new file mode 100755
index 000000000..6dfe74ce0
--- /dev/null
+++ b/2090/CH10/EX10.7/Chapter10_example7.sce
@@ -0,0 +1,29 @@
+clc
+clear
+//Input data
+v1=0.3;//Velocity of the pump plunger in m/s
+l=0.575;//The length of the fuel pipe in m
+A=1/20;//The cross sectional area of pipe to the plunger cylinder
+a=1/40;//The area of nozzle hole to the pipe 
+p1=27.6;//Initial pressure in the line in bar 
+p2=27.6;//The compression pressure of the engine
+K=17830*10^5;//The bulk modulus of fuel in N/m^2
+df=860;//The density of the fuel in kg/m^3
+pi=3.141;//Mathematical constant of pi
+
+//Calculations
+Vs=(K/df)^(1/2);//The velocity of pressure disturbances in m/s
+t=l/Vs;//Time taken by the disturbance to travel through pipe line in s
+Vp=(1/A)*v1;//The velocity of the fuel at the inlet of the pipe line in m/s
+p=[(K/Vs)*Vp]/10^5;//The change in pressure in bar
+pi=p+p1;//The pressure according to change in velocity in bar
+po=p1+p;//The change in total to the disturbance pressure in bar 
+vc=Vp-(a*((2*(po-p2))/df)^(1/2));//Change in the velocity in m/s
+pr=26.8;//By trail method the first reflected pressure wave from velocity in bar
+Vc=pr*(Vs/(K/10^5));//The change in velocity in m/s
+po1=p1+p+pr;//The pressure at the orifice end of the pipe in bar
+vo=a*((2*(po1-p2)*10^5)/df)^(1/2);//The velocity at the oriface end of the pipe in m/s
+
+//Output
+printf('(a)The velocity of the pressure disturbance = %3.0f m/s \n (b) The time taken by the disturbance to travel through the pipe line = %3.4f s \n (c) The velocity at the pump end of the pipe line as the plunger moves = %3.0f m/s \n The pressure at the pump end of the pipe line as the plunger moves =  %3.1f bar \n (d) The magnitude of the first reflected pressure = %3.2f bar \n The magnitude of the first reflected velocity wave = %3.2f m/s \n (e)The pressure at the oriface end of the pipe line after the first reflection = %3.1f bar \n The velocity at the oriface end of the pipe line after the first reflection = %3.2f m/s ',Vs,t,Vp,pi,pr,Vc,po1,vo)
+
-- 
cgit