From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 1979/CH8/EX8.6/Ex8_6.sce | 36 ++++++++++++++++++++++++++++++++++++ 1 file changed, 36 insertions(+) create mode 100755 1979/CH8/EX8.6/Ex8_6.sce (limited to '1979/CH8/EX8.6/Ex8_6.sce') diff --git a/1979/CH8/EX8.6/Ex8_6.sce b/1979/CH8/EX8.6/Ex8_6.sce new file mode 100755 index 000000000..674109f0a --- /dev/null +++ b/1979/CH8/EX8.6/Ex8_6.sce @@ -0,0 +1,36 @@ +//chapter-8 page 338 example 8.4 +//============================================================================== +clc; +clear; + +//For a reflex klystron +n=2;//peak mode value +V0=500;//beam voltage in V +Rsh=20000;//Shunt resistance in ohms +L=0.001;//distance in m +f=8*10^(9);////Operation frequency in Hz +V1=200;//microwave gap voltage in V +x=1.759*10^11;//e/m value in C/kg +J1=0.582; + +//CALCULATION +disp('Assume the gap transit time and beam loading are neglected'); +w=2*(%pi)*f;//angular frequency in rad +VR=(V0+((sqrt(8*V0/x)*w*L)/((2*(%pi)*n)-((%pi)/2))));//Repeller voltage in V +disp('Assuming output coupling coefficient Bo=1'); +I0=(V1/(2*J1*Rsh))/10^(-3);//Beam current necessary to obtain an microwave gap voltafe of 200V in mA +v0=0.593*10^6*sqrt(V0);//velocity of electron in m/sec +t0=((w*2*L*v0)/(x*(VR+V0)));//transit angle in rad +Bi=1;//beam coupling coefficient [assume] +X=((Bi*V1*t0)/(2*V0)); +disp('Since X=1.51, from graph,J1(X)=0.84'); +XJ1=0.84; +Eff=((2*(XJ1))/((2*n*(%pi))-((%pi)/2)))*100//Efficiency in % + +//OUTPUT +mprintf('\nRepeller voltage is VR=%3.2f V \nThe dc necessary to give an microwave gap voltafe of 200V is I0=%1.2f mA \nElectronic Efficiency is Eff=%2.2f percentage',VR,I0,Eff); + +//=========================END OF PROGRAM=============================== + +//Note: Check the answer for VR once +//Correct answer is Repeller voltage is VR=1189.36 V -- cgit