From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 1949/CH1/EX1.21/1_21.sce | 23 +++++++++++++++++++++++
 1 file changed, 23 insertions(+)
 create mode 100755 1949/CH1/EX1.21/1_21.sce

(limited to '1949/CH1/EX1.21')

diff --git a/1949/CH1/EX1.21/1_21.sce b/1949/CH1/EX1.21/1_21.sce
new file mode 100755
index 000000000..e54fadb6f
--- /dev/null
+++ b/1949/CH1/EX1.21/1_21.sce
@@ -0,0 +1,23 @@
+//Chapter-1,Example 1_21,Page 1-45
+clc()
+
+//Given Data:
+u=1.33                 //Refractive index of a soap film
+r=0                    //normal incidence
+t=5*10^-7              //thickness of film
+
+//Calculations:
+
+//Now, condition for maxima is
+//2ut*cos r=(2n-1)lam/2
+lam1=4*u*t*cos(r)/(2*1-1)          //n=1
+printf('For n=1 wavelength is =%.10f m \n',lam1)
+lam2=4*u*t*cos(r)/(2*2-1)          //n=2
+printf(' For n=2 wavelength is =%.10f m \n',lam2)
+lam3=4*u*t*cos(r)/(2*3-1)          //n=3
+printf(' For n=3 wavelength is =%.10f m \n',lam3)
+lam4=4*u*t*cos(r)/(2*4-1)          //n=4
+printf(' For n=4 wavelength is =%.10f m \n \n',lam4)
+
+printf(' Out of these wavelengths wavelength for n=3 lies in the visible spectrum. \n \n')
+printf(' Hence, wavelength for n=3 is the most reflected wavelength.')
-- 
cgit