From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 1871/CH4/EX4.33/Ch04Ex33.sce | 21 +++++++++++++++++++++
 1 file changed, 21 insertions(+)
 create mode 100755 1871/CH4/EX4.33/Ch04Ex33.sce

(limited to '1871/CH4/EX4.33')

diff --git a/1871/CH4/EX4.33/Ch04Ex33.sce b/1871/CH4/EX4.33/Ch04Ex33.sce
new file mode 100755
index 000000000..7817e4c68
--- /dev/null
+++ b/1871/CH4/EX4.33/Ch04Ex33.sce
@@ -0,0 +1,21 @@
+// Scilab code Ex4.33: : Pg:182 (2008)
+clc;clear;
+Lambda = 5.46e-05;    // Wavelength of light, cm
+n = 12;    // Number of fringes
+d = 0.40;    // Spacing between 12 fringes, cm
+omega = d/n;    // Fringe width, cm
+// Since fringe width in air wedge for normal incidence is given by omega = Lambda/2*theta. On solving for theta, we have
+// As omega = Lambda/(2*theta), solving for theta
+theta = Lambda/(2*omega);    // Angle of the wedge, radian
+l = 3;    // Length of the plate, cm
+t = theta*l;    // Thickness of the foil, cm
+mu = 1.33;    // Refractive index of water
+omega_prime = Lambda/(2*mu*theta);    // Fringe width if water is introduced in the wedge space in Newton's ring experiment, cm
+printf("\nThe angle of the wedge = %3.1e radian", theta);
+printf("\nThe thickness of the foil = %4.2e cm", t);
+printf("\nThe fringe width if water is introduced in the wedge space = %5.3f cm", omega_prime);
+
+// Result 
+// The angle of the wedge = 8.2e-004 radian
+// The thickness of the foil = 2.46e-003 cm
+// The fringe width if water is introduced in the wedge space = 0.025 cm 
\ No newline at end of file
-- 
cgit