From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 1835/CH8/EX8.1/Ex8_1.sce | 25 +++++++++++++++++++++++++
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 create mode 100755 1835/CH8/EX8.1/Ex8_1.sce

(limited to '1835/CH8/EX8.1/Ex8_1.sce')

diff --git a/1835/CH8/EX8.1/Ex8_1.sce b/1835/CH8/EX8.1/Ex8_1.sce
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+//CHAPTER 8 ILLUSRTATION 1 PAGE NO 221
+//TITLE:BALANCING OF ROTATING MASSES
+pi=3.141
+clc
+clear
+mA=12//       mass of A in kg
+mB=10//       mass of B in kg
+mC=18//       mass of C in kg
+mD=15//       mass of D in kg
+rA=40//       radius of A in mm
+rB=50//       radius of B in mm
+rC=60//       radius of C in mm
+rD=30//       radius of D in mm
+theta1=0//    angle between A-A in degrees
+theta2=60//   angle between A-B in degrees
+theta3=130//  angle between A-C in degrees
+theta4=270//  angle between A-D in degrees
+R=100//  radius at which mass to be determined in mm
+//====================================================
+Fh=(mA*rA*cosd(theta1)+mB*rB*cosd(theta2)+mC*rC*cosd(theta3)+mD*rD*cosd(theta4))/10//    vertical component value in kg cm
+Fv=(mA*rA*sind(theta1)+mB*rB*sind(theta2)+mC*rC*sind(theta3)+mD*rD*sind(theta4))/10//   horizontal component value in kg cm
+mb=(Fh^2+Fv^2)^.5/R*10//     unbalanced mass in kg
+theta=atand(Fv/Fh)//   position in degrees 
+THETA=180+theta//       angle with mA
+printf('magnitude of unbalaced mass=%.3f kg\n angle with mA= %.3f degrees',mb,THETA)
-- 
cgit