From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 1820/CH10/EX10.2/Example10_2.sce | 42 ++++++++++++++++++++++++++++++++++++++++
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+// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN
+// TURAN GONEN
+// CRC PRESS
+// SECOND EDITION
+
+// CHAPTER : 10 : PROTECTIVE EQUIPMENT AND TRANSMISSION SYSTEM PROTECTION
+
+// EXAMPLE : 10.2 :
+clear ; clc ; close ; // Clear the work space and console
+
+// GIVEN DATA
+// For case (a)
+I_f = 7.1428571 ; // Subtransient fault current in pu . Result of exa 10.1
+
+// For case (d)
+V_pf = 13800 ; // voltage in V
+zeta = 1.4 ;
+I_f1 = 7471 ; // magnitude of fault current in A
+
+// CALCULATIONS
+// For case (a)
+I_fdc_max = sqrt(2)*I_f ; // Max dc current in pu
+
+// For case (b)
+I_f_max = 2*I_fdc_max ; // Total max instantaneous current in pu
+
+// For case (c)
+I_momt = 1.6*I_f ; // Total rms momentary current
+
+// For case (d)
+S_int = sqrt(3)*(V_pf)*I_f1*zeta*10^-6 ; // Interrupting rating in MVA
+
+// For case (e)
+S_momt = sqrt(3)*(V_pf)*I_f1*1.6*10^-6 ; // Momentary duty of CB in MVA
+
+// DISPLAY RESULTS
+disp("EXAMPLE : 10.2 : SOLUTION :-") ;
+printf("\n (a) Maximum possible dc current component , I_fdc_max = %.1f pu \n",I_fdc_max) ;
+printf("\n (b) Total maximum instantaneous current , I_max = %.1f pu \n",I_f_max) ;
+printf("\n (c) Momentary current , I_momentary = %.2f pu \n",I_momt) ;
+printf("\n (d) Interrupting rating of a 2-cycle CB , S_interrupting = %.f MVA \n",S_int) ;
+printf("\n (e) Momentary duty of a 2-cycle CB , S_momentary = %.2f MVA \n",S_momt) ;
-- 
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