From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 1775/CH3/EX3.5/Chapter3_Example5.sce | 42 ++++++++++++++++++++++++++++++++++++
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+//Chapter-3, Illustration 5, Page 143
+//Title: Internal Combustion Engines
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+t=30;//duration of trial in minutes
+N=1750;//speed in rpm
+T=330;//brake torque in Nm
+m=9.35;//mass of fuel in kg
+CV=42300;//Calorific value in kJ/kg
+mj=483;//jacket cooling water circulation in kg
+Ti=290;//inlet temperature in K
+T0=350;//outlet temperature in K
+ma=182;//air consumption in kg
+Te=759;//exhaust temperature in K
+Ta=256;//atmospheric temperature in K
+nM=0.83;//Mechanical efficiency
+ms=1.25;//mean specific heat capacity of exhaust gas in kJ/kg-K
+Cw=4.18;//specific heat capacity of water in kJ/kg-K
+
+//CALCULATIONS
+BP=(2*3.1415*T*N)/(60*1000);//Brake power in kW
+sfc=(m*2)/BP;//specific fuel consumption in kg/kWh
+IP=BP/nM;//Indicated power in kW
+nIT=((IP*3600)/(m*CV*2))*100;//Indicated thermal efficiency
+Ef=(m*CV)/t;//Eneergy from fuel in kJ/min
+EBP=BP*60;//Energy to BP in kJ/min
+Ec=(mj*Cw*(T0-Ti))/t;//Energy to cooling water in kJ/min
+Ee=((ma+m)*ms*(Te-Ti))/30;//Energy to exhaust in kJ/min
+Es=Ef-(EBP+Ec+Ee);//Energy to surroundings in kJ/min
+
+//OUTPUT
+mprintf('Brake power is %3.1f kW \n Specific fuel consumption is %3.3f kg/kWh \n Indicated thermal efficiency is %3.1f percent \n Energy from fuel is %3.0f kJ/min \n Energy to BP is %3.0f kJ/min \n Energy to cooling water is %3.0f kJ/min \n Energy to exhaust is %3.0f kJ/min \n Energy to surroundings is %3.0f kJ/min',BP,sfc,nIT,Ef,EBP,Ec,Ee,Es)
+
+
+
+
+
+
+//==============================END OF PROGRAM=================================
-- 
cgit