From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 1757/CH6/EX6.10/EX6_10.sce | 27 +++++++++++++++++++++++++++
 1 file changed, 27 insertions(+)
 create mode 100755 1757/CH6/EX6.10/EX6_10.sce

(limited to '1757/CH6/EX6.10/EX6_10.sce')

diff --git a/1757/CH6/EX6.10/EX6_10.sce b/1757/CH6/EX6.10/EX6_10.sce
new file mode 100755
index 000000000..2f69e7ff4
--- /dev/null
+++ b/1757/CH6/EX6.10/EX6_10.sce
@@ -0,0 +1,27 @@
+//Example6.10  // To determine the range of the differential voltage gain
+clc;
+clear;
+close;
+//R1 = 1 K ohm to 25 K ohm ;
+R2 = 50 ; // K ohm
+R3 = 10 ;  // K ohm
+R4 = 10 ; // K ohm
+
+// the output of instrumentation amplifier is given by
+//Vo = (R4/R3)*(1+(2*R2/R1))*(VI@-VI1);
+
+// the differential voltage gain of the instrumentation amplifier can be written as
+//Av = (Vo/(VI2-VI1)) = (R4/R3)*(1+(2R2/R1));
+
+// For R1 = 1 K ohm   the maximum differential voltage gain of the instrumentation amplifier is
+R1 = 1 ; // K ohm
+Av = (R4/R3)*(1+(2*R2/R1));
+disp('the maximum differential voltage gain of the instrumentation amplifier is = '+string(Av)+ ' ');
+
+// For R1 = 25 K ohm   the mminimum differential voltage gain of the instrumentation amplifier is
+R1 = 25 ; // K ohm
+Av = (R4/R3)*(1+(2*R2/R1));
+disp('the minimum differential voltage gain of the instrumentation amplifier is = '+string(Av)+ ' ');
+
+disp(' the range of the differential voltage gain of the instrumentation amplifier is ');
+disp('                    5 <= Av <= 101 ');
-- 
cgit