From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 1757/CH14/EX14.11/EX14_11.sce | 65 +++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 65 insertions(+) create mode 100755 1757/CH14/EX14.11/EX14_11.sce (limited to '1757/CH14/EX14.11/EX14_11.sce') diff --git a/1757/CH14/EX14.11/EX14_11.sce b/1757/CH14/EX14.11/EX14_11.sce new file mode 100755 index 000000000..a1bb07abf --- /dev/null +++ b/1757/CH14/EX14.11/EX14_11.sce @@ -0,0 +1,65 @@ +// Example14.11 // Design a video amplifier of IC 1550 circuit +clc; +clear; +close; +Vcc = 12 ; // V +Av = -10 ; +Vagc = 0 ; // at bandwidth of 20 MHz +hfe = 50 ; // forward emitter parameter +rbb = 25 ; // ohm // base resistor +Cs = 1*10^-12 ; // F // source capacitor +Cl = 1*10^-12 ; // F // load capacitor +Ie1 = 1*10^-3 ; // A // emitter current of Q1 +f = 1000*10^6 ; // Hz +Vt = 52*10^-3 ; +Vt1 = 0.026 ; + +// When Vagc =0 the transistor Q2 is cut-off and the collector current of transistor Q2 flow through the transistor Q3 +// i.e Ic1=Ie1=Ie3 +Ie3 = 1*10^-3 ; // A // emitter current of Q3 +Ic1 = 1*10^-3 ; // A // collector current of the transistor Q1 + +// it indicates that the emitter current of Q2 is zero Ie2 = 0 then the emitter resistor of Q2 is infinite +re2 = %inf ; + +// emitter resistor of Q3 +re3 = (Vt/Ie1); +disp('The emitter resistor of Q3 is = '+string(re3)+' ohm '); + +// the trans conductance of transistor is +gm = (Ie1/Vt1); +disp('The trans conductance of transistor is = '+string(gm)+' A/V '); + +// the base emitter resistor rbe +rbe = (hfe/gm); +disp('The base emitter resistor rbe is = '+string(rbe)+' ohm '); + +// the emitter capacitor Ce +Ce = (gm/(2*%pi*f)); +disp('The emitter capacitor is = '+string(Ce)+' F '); + +// the voltage gain of video amplifier is +// Av = (Vo/Vin) ; +// Av = -((alpha3*gm)/(rbb*re3)*((1/rbb)+(1/rbe)+sCe)*((1/re2)+(1/re3)+sC3)*((1/Rl)+(s(Cs+Cl)))) + // At Avgc = 0 i.e s=0 in the above Av equation +alpha3 = 1 ; +s = 0 ; +Av =-10 ; +Rl = -((alpha3*gm)/((rbb*re3)*(((1/rbb)+(1/rbe))*((1/re2)+(1/re3))*(Av)))); +Rl = (1/Rl); +disp('The value of resistance RL is = '+string(Rl)+' ohm '); + +// there are three poles present in the transfer function of video amplifier each pole generate one 3-db frequency +Rl = 265 +fa = 1/(2*%pi*Rl*(Cs)); +disp('The pole frequency fa is = '+string(fa)+' Hz '); + + +fb = 1/(2*%pi*Ce*((rbb*rbe)/(rbb+rbe))); +disp('The pole frequency fb is = '+string(fb)+' Hz '); + +fc = 1/(2*%pi*Cs*re3); +disp('The pole frequency fc is = '+string(fc)+' Hz '); + +disp(' Hence fa is a dominant pole frequency '); + -- cgit