From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 167/CH13/EX13.2/ex2.sce | 48 ++++++++++++++++++++++++++++++++++++++++++++++++
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+//example 2
+//P-v-T Behavior of Nonideal Gas Mixtures
+clear
+clc
+NN2=2 //No.of kmol of N2
+NCO2=6 //No. of kmol of CO2
+Nm=8 // total no. of kmol of mixture
+Ru=8.314 //Universal gas constant in kPa-m^3/kmol-K
+Tm=300//Temp. of mixture in K
+Pm=15000 //Pressure of mixture in kPa
+Vm=Nm*Ru*Tm/Pm //volume of tank on the basis of ideal gas equation in m^3
+printf("\n Hence, the volume of the mixture on the basis of ideal gas equation of state is = %.3f m^3. \n",Vm);
+disp('Now,estimating volume of tank on the basis of Kays rule')
+yN2=NN2/Nm//mole fraction of nitrogen
+yCO2=NCO2/Nm //mole fraction of CO2
+TcrN2=126.2 // critical temop. of N2 in Kelvins
+TcrCO2=304.2 //critical temp. of CO2 in kelvins
+Tcrm=yN2*TcrN2+yCO2*TcrCO2 //pseudo critical temp. of mixture in Kelvins
+PcrN2=3.39 //critical pressure of N2 in MPa
+PcrCO2=7.39 //critical pressure in MPa
+Pcrm=yN2*PcrN2+yCO2*PcrCO2 //pseodo critical pressure of mixture in MPa
+Tm=300 //actual critical temp. of mixture in kelvins
+Pm=15 //actual critical pressure of mixture in MPa
+Tr=Tm/Tcrm //Reduced Temp. of mixture
+Pr=Pm/Pcrm //Reduced pressure of mixture
+Zm1=Tr/Pr //compressibility of the mixture
+Vm1=Zm1*Vm//volume of tank on the basis of Kays rule in m^3
+printf("\n Hence, the volume of the mixture on the basis of Kays rule is = %.3f m^3. \n",Vm1);
+disp('Now, estimating volume of tank on the basis of compressibility factors and Amagats law')
+TrN2=Tm/TcrN2 //Reduced Temp. of N2
+PrN2=Pm/PcrN2 //Reduced Pressure of N2
+ZN2=1.02 //compressibility factor of N2
+TrCO2=Tm/TcrCO2 //Reduced Temperature of CO2
+PrCO2=Pm/PcrCO2 //Reduced pressure of CO2
+ZCO2=0.30 //compressibility factor of CO2
+Zm2=ZN2*yN2+ZCO2*yCO2 //compressibility factor of the mixture
+Vm2=Zm2*Vm //volume of the mixture in m^3
+printf("\n Hence, the volume of the mixture on the basis of compressibility factors and Amagats law is = %.3f m^3. \n",Vm2);
+disp('Now, estimating volume of tank on the basis of compressibility factors and daltons law')
+VrN2=(Vm/NN2)/(Ru*TcrN2/(PcrN2*1000))
+VrCO2=(Vm/NCO2)/(Ru*TcrCO2/(PcrCO2*1000))
+ZN2=0.99 //compressibility factor of N2
+ZCO2=0.56 //compressibility factor of CO2
+Zm3=yN2*ZN2+yCO2*ZCO2 //compressibility factor of the mixture
+Vm3=Zm3*Vm //volume of the mixture in m^3
+disp('This is 33 percent lower than the assumed value. Therefore, we should repeat the calculations, using the new value of Vm. When the calculations are repeated we obtain 0.738 m^3 after the second iteration, 0.678 m^3 after the third iteration, and 0.648 m^3 after the fourth iteration. This value does not change with more iterations. Therefore')
+Vm=0.648 //volume of the mixture in m^3
+printf("\n Hence, the volume of the mixture on the basis of compressibility factors and Daltons law is = %.3f m^3. \n",Vm);
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-- 
cgit