From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 1583/CH2/EX2.8/Result_of_Chapter_2_Ex2_8.jpg | Bin 0 -> 156809 bytes 1583/CH2/EX2.8/SSA_Ex_2_8.sce | 13 +++++++++++++ 2 files changed, 13 insertions(+) create mode 100755 1583/CH2/EX2.8/Result_of_Chapter_2_Ex2_8.jpg create mode 100755 1583/CH2/EX2.8/SSA_Ex_2_8.sce (limited to '1583/CH2/EX2.8') diff --git a/1583/CH2/EX2.8/Result_of_Chapter_2_Ex2_8.jpg b/1583/CH2/EX2.8/Result_of_Chapter_2_Ex2_8.jpg new file mode 100755 index 000000000..f6e2b43bc Binary files /dev/null and b/1583/CH2/EX2.8/Result_of_Chapter_2_Ex2_8.jpg differ diff --git a/1583/CH2/EX2.8/SSA_Ex_2_8.sce b/1583/CH2/EX2.8/SSA_Ex_2_8.sce new file mode 100755 index 000000000..e9f698e68 --- /dev/null +++ b/1583/CH2/EX2.8/SSA_Ex_2_8.sce @@ -0,0 +1,13 @@ +clc +//Chapter 2:Small Signal Amplifiers +//example 2.8 page no 42 +//given +disp('Assuming Vi (input voltage)=1') +V1=(5+10^6)/(5+2*10^6)//voltage on the positive terminal +V2=10^6/(5+2*10^6)//the voltage on the inverting terminal +ed=V1-V2//differential voltage +ec=(V1+V2)/2//common-mode voltage +Ad=2*10^3//differentail gain +Ac=2*10^-3//common mode gain (here 20% of differentail gain) +Vo=Ad*ed+Ac*ec//actual amplifier output +mprintf('the voltage gain is %3.2e Volts',Vo) -- cgit