From f35ea80659b6a49d1bb2ce1d7d002583f3f40947 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:38:01 +0530
Subject: updated the code

---
 149/CH23/EX23.2/ex2.sce | 76 ++++++++++++++++++++++++-------------------------
 1 file changed, 38 insertions(+), 38 deletions(-)

(limited to '149/CH23/EX23.2')

diff --git a/149/CH23/EX23.2/ex2.sce b/149/CH23/EX23.2/ex2.sce
index a911a74f7..313e9064a 100755
--- a/149/CH23/EX23.2/ex2.sce
+++ b/149/CH23/EX23.2/ex2.sce
@@ -1,39 +1,39 @@
-clc
-disp('the first row of A represents the mid values of weekly earnings having interval of 2 in each class=x')
-A(1,:)=[11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41]
-disp('the second row denotes the no. of employees or in other words frequency=f')
-A(2,:)=[3 6 10 15 24 42 75 90 79 55 36 26 19 13 9 7]
-disp('third row denotes f*x')
-for i=1:16
-  A(3,i)=A(1,i)*A(2,i);
-end
-disp('fourth row denotes u=(x-25)/2')
-for i=1:16
-  A(4,i)=(A(1,i)-25)/2
-end
-disp('fifth row denotes f*x')
-for i=1:16
-  A(5,i)=A(4,i)*A(2,i);
-end
-A
-b=0;
-disp('sum of all elements of third row=')
-for i=1:16
-  b+=A(3,i)
-end
-disp(b)
-f=0;
-disp('sum of all elements of second row=')
-for i=1:16
-  f+=A(2,i)
-end
-disp(f)
-disp('mean=')
-b/f
-d=0;
-disp('sum of all elements of fifth row=')
-for i=1:16
-  d+=A(5,i)
-end
-disp('mean  by step deviation method=')
+clc
+disp('the first row of A represents the mid values of weekly earnings having interval of 2 in each class=x')
+A(1,:)=[11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41]
+disp('the second row denotes the no. of employees or in other words frequency=f')
+A(2,:)=[3 6 10 15 24 42 75 90 79 55 36 26 19 13 9 7]
+disp('third row denotes f*x')
+for i=1:16
+  A(3,i)=A(1,i)*A(2,i);
+end
+disp('fourth row denotes u=(x-25)/2')
+for i=1:16
+  A(4,i)=(A(1,i)-25)/2
+end
+disp('fifth row denotes f*x')
+for i=1:16
+  A(5,i)=A(4,i)*A(2,i);
+end
+A
+b=0;
+disp('sum of all elements of third row=')
+for i=1:16
+  b=A(3,i)
+end
+disp(b)
+f=0;
+disp('sum of all elements of second row=')
+for i=1:16
+  f=f+A(2,i)
+end
+disp(f)
+disp('mean=')
+b/f
+d=0;
+disp('sum of all elements of fifth row=')
+for i=1:16
+  d=d+A(5,i)
+end
+disp('mean  by step deviation method=')
 25+(2*d/f)
\ No newline at end of file
-- 
cgit