From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 1226/CH12/EX12.7/EX12_7.sce |  26 ++++++++++++++++++++++++++
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+clc;funcprot(0);//EXAMPLE 12.7
+// Initialisation of Variables
+n=6;...............//No of cylinders
+afr=20;...........//Air fuel ratio
+d = 0.1;...............//cylinder bore in mm
+l=0.14;..............//Cylinder length in mm
+etav=0.8;............//Volumetric Efficiency
+pa=1;.................//Pressure at the beginning of the compression in bar
+ta = 300;.............//Temperature at the beginning of the compression in Kelvin
+theta = 20;...............//Crank travel in degree for injection
+N = 1500;...................//engine rpm
+rhof=960;.................//Fuel density in kg/m^3
+cf=0.67;................//Co efficient of discharge for injector
+pi=150;....................//injection pressure in bar
+pc=40;....................//combustion pressure in bar
+R=287;........................//gas constant for air in kJ/kg.K
+//calculations
+V=(%pi/4)*d^2*l*etav;......................//Volume of air supplied per cylinder per cycle in m^3
+ma=(pa*10^5*V)/(R*ta);.....................//Mass of this air at suction conditions in kg/cycle
+mf=ma/afr;............................//Mass of fuel in kg/cycle
+fipc = (theta*60)/(360*N);...........//Time taken for fuel injection per cycle in seconds
+MF = mf/fipc;........................//Mass of fuel injected into each cylinder per second
+disp(MF,"The mass of fuel injected into each cylinder per second in kg/s :")
+vf=cf*sqrt((2*(pi-pc)*10^5)/rhof);.............//fuel velocity injection in m/s
+d0=sqrt((MF*4)/(%pi*vf*rhof));..................//diameter of fuel orifice in m
+disp(d0*1000,"Diameter of the fuel orifice in mm :")
-- 
cgit