From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 1052/CH7/EX7.3/3.sce | 26 ++++++++++++++++++++++++++
 1 file changed, 26 insertions(+)
 create mode 100755 1052/CH7/EX7.3/3.sce

(limited to '1052/CH7/EX7.3')

diff --git a/1052/CH7/EX7.3/3.sce b/1052/CH7/EX7.3/3.sce
new file mode 100755
index 000000000..aef6012d2
--- /dev/null
+++ b/1052/CH7/EX7.3/3.sce
@@ -0,0 +1,26 @@
+clc;
+//Example 7.3
+//page no 66, fig. 7.4
+printf("Example 7.3 page no 66,fig 7.4\n\n\n");
+//fluid device has four openings as shoen in figure
+//we have to calculate magnitude and direction of velocity,mass flow rate at section 4
+rho=800//density of fluid 
+v1=5//velocity at section 1
+S1=0.2//surface area at section 1
+v2=7//velocity at section 2
+S2=0.3//surface area at section 2
+v3=12//velocity at section 3
+S3=0.25//surface area at section 3
+S4=0.15//surface area at section 4
+printf("\n velocity v1=%f m/s \n surface area S1=%f m^2/s\n velocity v2=%f m/s\n surface area S2=%f m^2/s\n velocity v3=%f m/s\n surface area S3=%f m^2/s\n surface area S4=%f m^2/s",v1,S1,v2,S2,v3,S3,S4);
+q1=v1*S1//volumatric flow rate at section 1
+q2=v2*S2//volumatric flow rate at section 2
+q3=v3*S3//volumatric flow rate at section 3
+printf("\n volumatric flow rate q1=%f m^3/s\n volumatric flow rate q2=%f  m^3/s\n volumatrisc flow rate q3=%f m^3/s",q1,q2,q3);
+//applying continuity equation
+q4=q1+q2-q3//volumatric flow rate at section 4
+v4=q4/S4//velocity at section 4
+printf("\n volumatric flow rate q4=%f m^3/s\n velocity v4=%f m/s ",q4,v4);
+m=rho*q4//mass flow rate at section 4
+printf("\n mass flow rate m=%f kg/s",m);
+
-- 
cgit