From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 1019/CH7/EX7.7/Example_7_7.sce | 26 ++++++++++++++++++++++++++ 1 file changed, 26 insertions(+) create mode 100644 1019/CH7/EX7.7/Example_7_7.sce (limited to '1019/CH7/EX7.7/Example_7_7.sce') diff --git a/1019/CH7/EX7.7/Example_7_7.sce b/1019/CH7/EX7.7/Example_7_7.sce new file mode 100644 index 000000000..0e6bc6000 --- /dev/null +++ b/1019/CH7/EX7.7/Example_7_7.sce @@ -0,0 +1,26 @@ +//Example 7.7 +clear; +clc; + +//Given +R=0.08205;//gas constant in atm dm^3 K^-1 mol^-1 +R1=8.314;//gas constant in J K^-1 mol^-1 +T=293;//temperature in K +w1=100;//weight of ethanol taken in g +w2=100;//weight of methanol taken in g +p1=44.5;//vapour preaaure of pure ethanol in mm Hg +p2=88.7;//vapour preaaure of pure methanol in mm Hg + +//To determine the vapour pressure of solution,partial vapour pressures and vapour phase composition +n1=100/46;//moles of ethanol +n2=100/32;//moles of methanol +x1=n1/(n1+n2);//mole fraction of ethanol +x2=n2/(n1+n2);//mole fraction of methanol +P1=p1*x1;//partial pressure of ethanol in mm Hg +P2=p2*x2;//partial pressure of methanol in mm Hg +P=P1+P2;//vapour pressure of the solution in mm Hg +y1=P1/P;//mole fraction of ethanol in the vapour phase +y2=1-y1;//mole fraction of methanol in the vapour phase +mprintf('(i) Vapour pressure of the solution = %f',P); +mprintf('\n (ii) Partial vapour pressure of ethanol is %f mm Hg and that of methanol is %f mm Hg',P1,P2); +mprintf('\n (iii) mole fraction of ethanol in vapour phase is %f and that of methanol is %f',y1,y2); -- cgit