2 files changed, 46 insertions, 0 deletions
diff --git a/3886/CH4/EX4.4/4_4.txt b/3886/CH4/EX4.4/4_4.txt
new file mode 100644
index 000000000..b432b7c96
--- /dev/null
+++ b/3886/CH4/EX4.4/4_4.txt
@@ -0,0 +1,17 @@
+ 
+--> exec('E:\My program EM\4. Analysis of pin-jointed plane frames\Ex4_4.sce', -1)
+Required values are:-
+FHG=25.00 kN  (Compression)
+FHF=15.00 kN  (Tension)
+RG=42.00 kN
+VA=10.00 kN  (Downwards)
+HA=0.00 kN
+FAC=18.03 kN  (Compression)
+FAB=15.00 kN  (Tension)
+FBC=0.00 kN
+FCE=18.03 kN  (Compression)
+FDE=0.00 kN
+FDF=15.00 kN  (Tension)
+FEF=0.00 kN
+FEG=18.03 kN  (Compression)
+FAG=12.00 kN  (Compression)
+\ No newline at end of file
diff --git a/3886/CH4/EX4.4/Ex4_4.sce b/3886/CH4/EX4.4/Ex4_4.sce
new file mode 100644
index 000000000..92223721f
--- /dev/null
+++ b/3886/CH4/EX4.4/Ex4_4.sce
@@ -0,0 +1,29 @@
+//Finding forces in all members
+//Refer fig. 4.11(a)
+theta1=atand(4/6)  //Degree
+theta2=atand(8/6)  //Degree
+theta3=atand(4/3)  //Degree
+//Joint H
+FHG=20/sind(53.13)  //kN  (Compression)
+FHF=25*cosd(53.13)  //kN  (Tension)
+//Taking moment about A
+RG=(20*9+12*6)/6  //kN
+VA=32-42  //kN  (Downwards)
+HA=0
+//Joint A
+//applying equilibrium conditions
+FAC=10/sind(33.69)  //kN  (Compression)
+FAB=18.03*cosd(33.69)  //kN  (Tension)
+//Joint B
+FBC=0
+FCE=FAC  //kN  (Compression)
+//Joint D
+FDE=0
+FDF=FBD  //kN  (Tension)
+//Joint E
+FEF=0
+FEG=FCE  //kN  (Compression)
+//Joint F
+FAG=12  //kN  (Compression)
+printf("Required values are:-\nFHG=%.2f kN  (Compression)\nFHF=%.2f kN  (Tension)\nRG=%.2f kN\nVA=%.2f kN  (Downwards)\nHA=%.2f kN\nFAC=%.2f kN  (Compression)\nFAB=%.2f kN  (Tension)\nFBC=%.2f kN\nFCE=%.2f kN  (Compression)\nFDE=%.2f kN\nFDF=%.2f kN  (Tension)\nFEF=%.2f kN\nFEG=%.2f kN  (Compression)\nFAG=%.2f kN  (Compression)",FHG,FHF,RG,-VA,HA,FAC,FAB,FBC,FCE,FDE,FDF,FEF,FEG,FAG)
+