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+//Composite pulley
+//refer fig. 20.7 (a) and (b)
+//Let aA be acceleration of 4000 N block and aB that of 2000 N block,and alpha be the angular velocity of pulley, then
+//aA=0.5*alpha
+//aB=0.75*alpha
+//Writing dynamic equilibrium equation for the two blocks and from kinetic equation of pulley
+alpha=500/245.97 //rad/sec^2
+TA=4000*(1-(0.5*2.033)/(9.81)) //N
+TB=2000*(1+(0.75*2.033)/(9.81)) //N
+printf("\nalpha=%.3f rad/sec^2\nTA=%.3f N\nTB=%.3f N",alpha,TA,TB)