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-rw-r--r--3886/CH16/EX16.1/16_1.sce15
-rw-r--r--3886/CH16/EX16.1/16_1.txt4
-rw-r--r--3886/CH16/EX16.10/16_10.sce16
-rw-r--r--3886/CH16/EX16.10/16_10.txt4
-rw-r--r--3886/CH16/EX16.11/16_11.sce10
-rw-r--r--3886/CH16/EX16.11/16_11.txt5
-rw-r--r--3886/CH16/EX16.12/16_12.sce16
-rw-r--r--3886/CH16/EX16.12/16_12.txt5
-rw-r--r--3886/CH16/EX16.13/16_13.sce23
-rw-r--r--3886/CH16/EX16.13/16_13.txt4
-rw-r--r--3886/CH16/EX16.2/16_2.sce28
-rw-r--r--3886/CH16/EX16.2/16_2.txt5
-rw-r--r--3886/CH16/EX16.3/16_3.sce19
-rw-r--r--3886/CH16/EX16.3/16_3.txt3
-rw-r--r--3886/CH16/EX16.4/16_4.sce21
-rw-r--r--3886/CH16/EX16.4/16_4.txt4
-rw-r--r--3886/CH16/EX16.5/16_5.sce26
-rw-r--r--3886/CH16/EX16.5/16_5.txt5
-rw-r--r--3886/CH16/EX16.6/16_6.sce10
-rw-r--r--3886/CH16/EX16.6/16_6.txt4
-rw-r--r--3886/CH16/EX16.7/16_7.sce20
-rw-r--r--3886/CH16/EX16.7/16_7.txt5
-rw-r--r--3886/CH16/EX16.8/16_8.sce18
-rw-r--r--3886/CH16/EX16.8/16_8.txt4
-rw-r--r--3886/CH16/EX16.9/16_9.sce16
-rw-r--r--3886/CH16/EX16.9/16_9.txt4
26 files changed, 294 insertions, 0 deletions
diff --git a/3886/CH16/EX16.1/16_1.sce b/3886/CH16/EX16.1/16_1.sce
new file mode 100644
index 000000000..658726feb
--- /dev/null
+++ b/3886/CH16/EX16.1/16_1.sce
@@ -0,0 +1,15 @@
+//Pump
+//Work done in lifting 40 m^3 of water to a height of 50 m (W1)
+W1=40*9810*50 //N-m
+//Kinetic energy at delivery KE1
+KE1=(40*9810*25)/(2*9.81) //N-m
+//Total energy spent (TE)
+TE=19620000+500000 //N-m
+//This energy is spent by the pump in half an hour
+//Pump output power (PO)
+PO=(20120000)/(1800*1000) //kW
+//Input power (Ip)
+Ip=PO/0.7 //kW
+printf("\Energy spent=%.2f N-m\nInput power=%.4f kW",TE,Ip)
+
+
diff --git a/3886/CH16/EX16.1/16_1.txt b/3886/CH16/EX16.1/16_1.txt
new file mode 100644
index 000000000..84c50c4cb
--- /dev/null
+++ b/3886/CH16/EX16.1/16_1.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.1.sce', -1)
+Energy spent=20120000.00 N-m
+Input power=15.9683 kW \ No newline at end of file
diff --git a/3886/CH16/EX16.10/16_10.sce b/3886/CH16/EX16.10/16_10.sce
new file mode 100644
index 000000000..0a8eaf629
--- /dev/null
+++ b/3886/CH16/EX16.10/16_10.sce
@@ -0,0 +1,16 @@
+//Body A
+//refer fig. 16.14
+mu=0.2
+//let theta1 and theta2 be the slopes of the inclined planes
+//sind(thets1)=4/5 cosd(theta1)=0.6
+//sind(theta2)=3/5 cosd(theta2)=0.8
+//1500*sind(theta1)=1200 N down the plane
+F1=mu*1500*0.6 //N up the plane
+F2=0.2*2000*0.8 //N down the plane
+//Equating work done to change in kinetic energy
+//v=3 m/sec
+s=((1500*3*3+2000*1.5*1.5)/(2*9.81*260)) //m
+printf("\nThus s=%.3f m",s)
+
+
+
diff --git a/3886/CH16/EX16.10/16_10.txt b/3886/CH16/EX16.10/16_10.txt
new file mode 100644
index 000000000..ec68dd228
--- /dev/null
+++ b/3886/CH16/EX16.10/16_10.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.10.sce', -1)
+
+Thus s=3.529 m \ No newline at end of file
diff --git a/3886/CH16/EX16.11/16_11.sce b/3886/CH16/EX16.11/16_11.sce
new file mode 100644
index 000000000..4c37ae884
--- /dev/null
+++ b/3886/CH16/EX16.11/16_11.sce
@@ -0,0 +1,10 @@
+//Two bodies hung to rope
+//refer fig. 16.15 (a) and (b)
+s=(450+300)*(4*4-2*2)/(2*9.81*150) //m
+//Let T be the tension in the string
+//apply work energy principle
+T=((450*3.058)-((450*12)/(2*9.81)))/3.058 //N
+printf("\nT=%.0f N\ns=%.3f m",T,s)
+
+
+
diff --git a/3886/CH16/EX16.11/16_11.txt b/3886/CH16/EX16.11/16_11.txt
new file mode 100644
index 000000000..b897d5e10
--- /dev/null
+++ b/3886/CH16/EX16.11/16_11.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.11.sce', -1)
+
+T=360 N
+s=3.058 m \ No newline at end of file
diff --git a/3886/CH16/EX16.12/16_12.sce b/3886/CH16/EX16.12/16_12.sce
new file mode 100644
index 000000000..d758c5937
--- /dev/null
+++ b/3886/CH16/EX16.12/16_12.sce
@@ -0,0 +1,16 @@
+//Block slides down a plane
+//refer fig. 16.17 and 16.18
+N=3000*cosd(50) //N
+mu=0.2
+F=mu*N //N
+//let the maximum deformation of the spring be s mm
+//then
+s=721.43 //mm
+//Velocity will be maximum when the acceleration is zero
+//Let x be the deformation when net force on the body in the direction of motion is zero
+x=(3000*sind(50)-385.67)/(20) //mm
+//applying work energy principle
+v=5.061 //m/sec
+printf("\nv=%.3f m/sec\ns=%.3f mm",v,s)
+
+
diff --git a/3886/CH16/EX16.12/16_12.txt b/3886/CH16/EX16.12/16_12.txt
new file mode 100644
index 000000000..60a948d58
--- /dev/null
+++ b/3886/CH16/EX16.12/16_12.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.12.sce', -1)
+
+v=5.061 m/sec
+s=721.430 mm \ No newline at end of file
diff --git a/3886/CH16/EX16.13/16_13.sce b/3886/CH16/EX16.13/16_13.sce
new file mode 100644
index 000000000..541f1bcdf
--- /dev/null
+++ b/3886/CH16/EX16.13/16_13.sce
@@ -0,0 +1,23 @@
+//Wagon strikes bumper post
+//refer fig. 16.19
+W=500
+//Component of weight down the plane Wd
+Wd=W/100 //kN
+//Track resistance Rt
+Rt=2.5 //kN
+//u=0
+s=30 //m
+//Let the velocity of wagon while striking be v m/sec
+//Applying work energy equation
+v=1.716 //m/sec
+//Let spring compresion be x
+k=15000 //kN/m
+//Applying work energy equation and solving quadratic equation
+x=100.2 //mm
+printf("\nThe spring will be compressed by %.1f mm",x)
+
+
+
+
+
+
diff --git a/3886/CH16/EX16.13/16_13.txt b/3886/CH16/EX16.13/16_13.txt
new file mode 100644
index 000000000..2375bf47b
--- /dev/null
+++ b/3886/CH16/EX16.13/16_13.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.13.sce', -1)
+
+The spring will be compressed by 100.2 mm \ No newline at end of file
diff --git a/3886/CH16/EX16.2/16_2.sce b/3886/CH16/EX16.2/16_2.sce
new file mode 100644
index 000000000..fac3e4695
--- /dev/null
+++ b/3886/CH16/EX16.2/16_2.sce
@@ -0,0 +1,28 @@
+//Man and his wish
+//refer fig. 16.4 (a),(b)
+//Work done in sliding
+N=1 //kN
+W=N //kN
+mu=0.3
+F=mu*N //kN
+//Applied force
+P=F //kN
+//Work to be done in sliding to a distance of 5 m (W1)
+W1=0.3*5 //kJ
+//Work to be done in tipping
+//Height (h)
+h=(1/sqrt(2))-0.5 //m
+//Work done in one tipping (W2)
+W2=W*h //kJ
+//To move a distance of 5m, Five tippings are required
+//Hence
+W3=5*W2 //kJ
+printf("\nThe man needs to spend only %.2f kJ while tipping and it is less than %.2f kJ spent in sliding\nHe should move the box by tipping",W3,W1)
+
+
+
+
+
+
+
+
diff --git a/3886/CH16/EX16.2/16_2.txt b/3886/CH16/EX16.2/16_2.txt
new file mode 100644
index 000000000..54554555b
--- /dev/null
+++ b/3886/CH16/EX16.2/16_2.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.2.sce', -1)
+
+The man needs to spend only 1.04 kJ while tipping and it is less than 1.50 kJ spent in sliding
+He should move the box by tipping \ No newline at end of file
diff --git a/3886/CH16/EX16.3/16_3.sce b/3886/CH16/EX16.3/16_3.sce
new file mode 100644
index 000000000..037cb8404
--- /dev/null
+++ b/3886/CH16/EX16.3/16_3.sce
@@ -0,0 +1,19 @@
+//body pushed up the plane
+//refer fig. 16.6
+//applying equilibrium condition
+N=300*cosd(30) //N
+mu=0.2
+//Frictional force
+F=mu*N //N
+//initial velocity
+u=1.5 //m/sec
+//displacement
+s=6 //m
+//let final velocity be v m/sec
+//Equating work done by forces along the plane to change in K.E
+v=sqrt(77.71+2.25) //m/sec
+printf("After moving 6 m the body will have velocity v=%.4f m/sec",v)
+
+
+
+
diff --git a/3886/CH16/EX16.3/16_3.txt b/3886/CH16/EX16.3/16_3.txt
new file mode 100644
index 000000000..cfd2b040a
--- /dev/null
+++ b/3886/CH16/EX16.3/16_3.txt
@@ -0,0 +1,3 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.3.sce', -1)
+After moving 6 m the body will have velocity v=8.9420 m/sec \ No newline at end of file
diff --git a/3886/CH16/EX16.4/16_4.sce b/3886/CH16/EX16.4/16_4.sce
new file mode 100644
index 000000000..6c6ef94d5
--- /dev/null
+++ b/3886/CH16/EX16.4/16_4.sce
@@ -0,0 +1,21 @@
+//Power of a locomotive
+//refer fig.16.7 (a) and (b)
+v=(56*1000)/(60*60) //m/sec
+F=5*420/1000 //kN
+W=420 //kN
+P=F+W*(1/120) //kN
+//Power of Locomotive Pw
+Pw=P*v //kW (mistake in book)
+u=15.556 //m/sec
+//Resultant force parallel to the plane R
+R=F+W*sind(theta) //kN (Down the plane)
+s=((420*(15.556^2))/(2*9.81*5.6)) //m
+printf("Power of locomotive=%.4f kW\ns=%.4f m",Pw,s)
+//The answers vary due to round off error
+
+
+
+
+
+
+
diff --git a/3886/CH16/EX16.4/16_4.txt b/3886/CH16/EX16.4/16_4.txt
new file mode 100644
index 000000000..1fecd1e8a
--- /dev/null
+++ b/3886/CH16/EX16.4/16_4.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.4.sce', -1)
+Power of locomotive=87.1111 kW
+s=925.0349 m \ No newline at end of file
diff --git a/3886/CH16/EX16.5/16_5.sce b/3886/CH16/EX16.5/16_5.sce
new file mode 100644
index 000000000..aba7c080d
--- /dev/null
+++ b/3886/CH16/EX16.5/16_5.sce
@@ -0,0 +1,26 @@
+//A tram car
+//refer fig.16.8 (a),(b) and (c)
+//frictional resistance
+W=120 //kN
+F=5*120/1000 //kN
+v=(20*1000)/(60*60) //m/sec
+// (1) on level track
+P1=F //kN
+//output power Pw1
+Pw1=P1*v //kW
+eta1=0.8
+//input power Ip1
+Ip1=Pw1/0.8 //kW
+// (2) Up the plane
+P2=F+W*(1/300) //kN
+//output power required Pw2
+Pw2=P2*v //kW
+//Input power of engine Ip2
+Ip2=Pw2/0.8 //kW
+// (3) Down the incline plane
+Pd=F-W*(1/300)
+Pwd=0.2*5.5556 //kW
+//Input power
+Ipd=1.1111/0.8 //kW
+printf("\On level track Input Power=%.3f kW\nUp the plane Input Power=%.3f kW\nDown the incline plane Input Power=%.3f kW",Ip1,Ip2,Ipd)
+
diff --git a/3886/CH16/EX16.5/16_5.txt b/3886/CH16/EX16.5/16_5.txt
new file mode 100644
index 000000000..2eba45c68
--- /dev/null
+++ b/3886/CH16/EX16.5/16_5.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.5.sce', -1)
+On level track Input Power=4.167 kW
+Up the plane Input Power=6.944 kW
+Down the incline plane Input Power=1.389 kW \ No newline at end of file
diff --git a/3886/CH16/EX16.6/16_6.sce b/3886/CH16/EX16.6/16_6.sce
new file mode 100644
index 000000000..564987fc4
--- /dev/null
+++ b/3886/CH16/EX16.6/16_6.sce
@@ -0,0 +1,10 @@
+//Police investigation
+//refer fig. 16.9
+//Let the probable speed of the car just before brakes are applied be u m/sec
+//F=0.5*W
+//Final velocity=0
+s=60 //m
+//applying work energy equation
+u=((sqrt(0.5*60*2*9.81))*60*60)/1000 //m/sec
+printf("\nThe probable speed of the car just before brakes are applied is %.2f kmph",u)
+
diff --git a/3886/CH16/EX16.6/16_6.txt b/3886/CH16/EX16.6/16_6.txt
new file mode 100644
index 000000000..a73233fe0
--- /dev/null
+++ b/3886/CH16/EX16.6/16_6.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.6.sce', -1)
+
+The probable speed of the car just before brakes are applied is 87.34 kmph \ No newline at end of file
diff --git a/3886/CH16/EX16.7/16_7.sce b/3886/CH16/EX16.7/16_7.sce
new file mode 100644
index 000000000..8e351d1bc
--- /dev/null
+++ b/3886/CH16/EX16.7/16_7.sce
@@ -0,0 +1,20 @@
+//Block being pulled
+//refer fig. 16.10 (a) and (b)
+//when pull P is acting
+W=2500 //N
+P=1000 //N
+N=W-P*sind(30)
+mu=0.2
+F=mu*N //N
+//Initial velocity=0
+//Let final velocity be v
+s=30 //m
+//Applying work energy equation for the horizontal motion
+v=sqrt((0.866*1000-400)*30*2*9.81/2500)
+printf("\nv=%.3f m/sec",v)
+//Now if the 1000 N force is removed,let the distance moved before rest be s
+//Initial velocity=10.4745 //m/sec
+//Final velocity=0
+s=(2500*(10.4745^2))/(400*2*9.81) //m
+printf("\ns=%.3f m",s)
+//The answer provided in the textbook is wrong
diff --git a/3886/CH16/EX16.7/16_7.txt b/3886/CH16/EX16.7/16_7.txt
new file mode 100644
index 000000000..5f5014663
--- /dev/null
+++ b/3886/CH16/EX16.7/16_7.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.7.sce', -1)
+
+v=10.474 m/sec
+s=34.950 m \ No newline at end of file
diff --git a/3886/CH16/EX16.8/16_8.sce b/3886/CH16/EX16.8/16_8.sce
new file mode 100644
index 000000000..1c5e9f496
--- /dev/null
+++ b/3886/CH16/EX16.8/16_8.sce
@@ -0,0 +1,18 @@
+//Small block sliding down the plane
+//refer fig. 16.11 (a),(b) and (c)
+//Length AB
+AB=sqrt((3^2)+(4^2))
+//Consider FBD of the block on inclined plane A
+//It moves down the plane, hence
+//N1=W*0.8
+mu=0.3
+//F1=0.3*W
+//Applying work energy equation for the motion from A to B
+vB=sqrt((0.6-0.24)*5*2*9.81) //m/sec
+//For the motion on horizontal plane
+//final velocity=0
+//Writing work energy equation for the motion along BC
+s=(5.943^2)/(2*9.81*0.3) //m
+printf("\ns=%.2f m",s)
+
+
diff --git a/3886/CH16/EX16.8/16_8.txt b/3886/CH16/EX16.8/16_8.txt
new file mode 100644
index 000000000..ee1b89366
--- /dev/null
+++ b/3886/CH16/EX16.8/16_8.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.8.sce', -1)
+
+s=6.00 m \ No newline at end of file
diff --git a/3886/CH16/EX16.9/16_9.sce b/3886/CH16/EX16.9/16_9.sce
new file mode 100644
index 000000000..9dcdf4232
--- /dev/null
+++ b/3886/CH16/EX16.9/16_9.sce
@@ -0,0 +1,16 @@
+//Force P required
+//refer fig. 16.13 (a),(b)
+//The system of forces acting on connecting bodies is shown in figure
+N1=250 //N
+mu=0.3
+F1=mu*N1 //N
+N2=(1000*3)/(5) //N
+F2=0.3*N2 //N
+N3=500 //N
+F3=mu*N3 //N
+//Let the constant force be P
+//writing work energy equation
+P=((250+1000+500)*3*3/(2*9.81*4.5))+75+180+1000*0.8+150 //N
+printf("\nThus P=%.3f N",P)
+
+
diff --git a/3886/CH16/EX16.9/16_9.txt b/3886/CH16/EX16.9/16_9.txt
new file mode 100644
index 000000000..4b2cf51c1
--- /dev/null
+++ b/3886/CH16/EX16.9/16_9.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\16. Work energy method\16.9.sce', -1)
+
+Thus P=1383.389 N \ No newline at end of file
generated by cgit (git 2.34.1) at 2024-12-19 16:48:48 +0000