22 files changed, 261 insertions, 0 deletions

diff --git a/3886/CH14/EX14.1/14_1.sce b/3886/CH14/EX14.1/14_1.sce
new file mode 100644
index 000000000..c8cad45f6
--- /dev/null
+++ b/3886/CH14/EX14.1/14_1.sce
@@ -0,0 +1,10 @@
+//Passenger train

+//refer fig. 14.7

+//let vb= velocity of goods train

+vA=(72*1000)/(60*60)  //m/sec

+//relative velocity of B w.r.t A

+//vB/A=20-vB

+//relative distance moved to overtake the goods train=250+200 m

+//45 seconds are required to cover this relative distance

+vB=(10*60*60)/(1000)  //kmph

+printf("\nvB=%.2f kmph",vB)

diff --git a/3886/CH14/EX14.1/14_1.txt b/3886/CH14/EX14.1/14_1.txt
new file mode 100644
index 000000000..abfe1c8a8
--- /dev/null
+++ b/3886/CH14/EX14.1/14_1.txt
@@ -0,0 +1,4 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.1.sce', -1)

+

+vB=36.00 kmph
\ No newline at end of file
diff --git a/3886/CH14/EX14.10/14_10.sce b/3886/CH14/EX14.10/14_10.sce
new file mode 100644
index 000000000..94f37567f
--- /dev/null
+++ b/3886/CH14/EX14.10/14_10.sce
@@ -0,0 +1,22 @@
+//Jet of water

+//refer fig. 14.18 and 14.19

+//time taken to move a horizontal distance of 5m

+t=5/20  //sec

+//During this period vertical downward velocity gained by water (Vw)

+Vw=0+(9.81/4)

+//Horizontal component of velocity of plate (HCp)

+HCp=0

+//Vertical component of velocity of plate (VCp)

+VCp=1  //m/sec

+//relative velocity of water w.r.t. plate

+vry=Vw-VCp  //m/sec

+vrx=20  //m/sec

+vr=sqrt((20)^2+(1.453)^2)  //m/sec

+alpha=atand(1.453/20)  //degree

+printf("\nvr=%.2f m/sec\nalpha=%.2f degree",vr,alpha)

+

+

+

+

+

+

diff --git a/3886/CH14/EX14.10/14_10.txt b/3886/CH14/EX14.10/14_10.txt
new file mode 100644
index 000000000..5757095bd
--- /dev/null
+++ b/3886/CH14/EX14.10/14_10.txt
@@ -0,0 +1,5 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.10.sce', -1)

+

+vr=20.05 m/sec

+alpha=4.16 degree
\ No newline at end of file
diff --git a/3886/CH14/EX14.11/14_11.sce b/3886/CH14/EX14.11/14_11.sce
new file mode 100644
index 000000000..f902e8589
--- /dev/null
+++ b/3886/CH14/EX14.11/14_11.sce
@@ -0,0 +1,23 @@
+//railway carriage

+//refer fig. 14.20

+//Velocity of components of train are

+v1x=96  //kmph

+v1y=0

+//Velocity components of bullet are

+//v2x=0.9848*v

+//v2y=0.1736*v

+//Component of relative velocity of B w.r.t. A are

+//vrx=0.9848*v-96

+//vry=0.1736*v

+//Direction of relative velocity alpha with x-axis

+//tand(alpha)=((vry)/(vrx))

+//thus

+v=183.96  //kmph  

+//consider motion in y direction

+vry=0.1736*51.1  //m/sec

+//Time period (t)

+t=(1.8)/(0.1736*51.1)  //sec

+printf("\nv=%.2f kmph\nt=%.3f sec",v,t)

+

+

+

diff --git a/3886/CH14/EX14.11/14_11.txt b/3886/CH14/EX14.11/14_11.txt
new file mode 100644
index 000000000..618f69e04
--- /dev/null
+++ b/3886/CH14/EX14.11/14_11.txt
@@ -0,0 +1,5 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.11.sce', -1)

+

+v=183.96 kmph

+t=0.203 sec
\ No newline at end of file
diff --git a/3886/CH14/EX14.2/14_2.sce b/3886/CH14/EX14.2/14_2.sce
new file mode 100644
index 000000000..ea302b69e
--- /dev/null
+++ b/3886/CH14/EX14.2/14_2.sce
@@ -0,0 +1,13 @@
+//passenger train

+//velocity

+vA=20  //m/sec

+//let velocity of goods train be vB m/sec

+//relative velocity=20-vB m/sec

+//when t=25 relative distance moved is x metres

+//(20-vB)*25=x

+//In the next t=30 seconds

+//relative distance moved=length of passenger train=240 m

+vB=(20-(240/30))*((60*60)/(1000)) //km/h

+x=(20-12)*25  //m

+printf("\nLength is %.2f m\nSpeed is %.2f km/h",x,vB)

+

diff --git a/3886/CH14/EX14.2/14_2.txt b/3886/CH14/EX14.2/14_2.txt
new file mode 100644
index 000000000..db648b8c2
--- /dev/null
+++ b/3886/CH14/EX14.2/14_2.txt
@@ -0,0 +1,5 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.2.sce', -1)

+

+Length is 200.00 m

+Speed is 43.20 km/h
\ No newline at end of file
diff --git a/3886/CH14/EX14.3/14_3.sce b/3886/CH14/EX14.3/14_3.sce
new file mode 100644
index 000000000..125117821
--- /dev/null
+++ b/3886/CH14/EX14.3/14_3.sce
@@ -0,0 +1,8 @@
+//Two trains

+//Taking the direction of motion of train A as positive

+//let velocity of A be v m/sec

+//Relative velocity=1.5*v

+vA=20*((60*60)/(1000))  //kmph

+//velocity of B

+vB=-10*((60*60)/(1000))  //kmph

+printf("\nVelocity of A=%.2f kmph\nVelocity of B=%.2f kmph",vA,-vB)

diff --git a/3886/CH14/EX14.3/14_3.txt b/3886/CH14/EX14.3/14_3.txt
new file mode 100644
index 000000000..fbdc6bc01
--- /dev/null
+++ b/3886/CH14/EX14.3/14_3.txt
@@ -0,0 +1,5 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.3.sce', -1)

+

+Velocity of A=72.00 kmph

+Velocity of B=36.00 kmph
\ No newline at end of file
diff --git a/3886/CH14/EX14.4/14_4.sce b/3886/CH14/EX14.4/14_4.sce
new file mode 100644
index 000000000..f8bb4e9d4
--- /dev/null
+++ b/3886/CH14/EX14.4/14_4.sce
@@ -0,0 +1,18 @@
+//Two ships

+//refer fig.14.8,14.9 and 14.10

+//Taking west direction as x-axis and north direction as y-axis

+//velocities in kmph are

+vAx=30*sind(30)

+vAy=30*cosd(30)

+vBx=40*sind(45)

+vBy=-40*sind(45)

+vrx=15-28.284

+vry=25.98-(-28.284)

+vr=sqrt((13.284^2)+(54.264^2))

+theta=atand((13.284)/(54.264))  //degree

+printf("\nFrom B, ship A appears to move with a velocity of %.2f kmph in N %.2f degree E direction",vr,theta)

+//relative distance after half an hour (drel)

+drel=55.866*(1/2)  //km

+printf("\nRelative distance after half an hour=%.2f km",drel)

+

+

diff --git a/3886/CH14/EX14.4/14_4.txt b/3886/CH14/EX14.4/14_4.txt
new file mode 100644
index 000000000..cc391eaf6
--- /dev/null
+++ b/3886/CH14/EX14.4/14_4.txt
@@ -0,0 +1,5 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.4.sce', -1)

+

+From B, ship A appears to move with a velocity of 55.87 kmph in N 13.76 degree E direction

+Relative distance after half an hour=27.93 km
\ No newline at end of file
diff --git a/3886/CH14/EX14.5/14_5.sce b/3886/CH14/EX14.5/14_5.sce
new file mode 100644
index 000000000..4bb4f42db
--- /dev/null
+++ b/3886/CH14/EX14.5/14_5.sce
@@ -0,0 +1,26 @@
+//Enemy ship location

+//refer fig. 14.10

+//taking north as y direction and west as x direction

+//vAy=36*cosd(theta)

+//vAx=36*sind(theta)

+//Components of velocity of enemy ship

+vBy=18*cosd(30)  //kmph

+vBx=-18*sind(30)  //kmph

+//then

+//vrx=36*sind(theta)+9

+//vry=36*cosd(theta)-15.588

+//solving

+x=0.2777

+theta=16.12  //degree

+printf("\nWar ship must move in N %.2f W direction",theta)

+vrx=36*sind(theta)+9

+vry=36*cosd(theta)-15.588

+vr=sqrt((19^2)+(19^2))  //kmph

+//relative distance moved

+dr=25-5  //km

+//time interval 

+t=20/26.870  //hour

+printf("\n%.2f hour after sighting the enemy ship the shell is to be fired",t)

+

+

+  

diff --git a/3886/CH14/EX14.5/14_5.txt b/3886/CH14/EX14.5/14_5.txt
new file mode 100644
index 000000000..b54896698
--- /dev/null
+++ b/3886/CH14/EX14.5/14_5.txt
@@ -0,0 +1,5 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.5.sce', -1)

+

+War ship must move in N 16.12 W direction

+0.74 hour after sighting the enemy ship the shell is to be fired
\ No newline at end of file
diff --git a/3886/CH14/EX14.6/14_6.sce b/3886/CH14/EX14.6/14_6.sce
new file mode 100644
index 000000000..fed361c26
--- /dev/null
+++ b/3886/CH14/EX14.6/14_6.sce
@@ -0,0 +1,16 @@
+//Motor boat crossing river

+//refer fig. 14.11 and 14.12

+//let the motor boat start from A and reaches C

+vrx=15  //kmph

+//distance to be moved in x direction=1 km

+//time required t is

+t=4  //min

+//boat will move down the stream

+vy=5  //kmph

+//Distance moved in downstream direction (d)

+d=333.33  //m

+//Let the direction of boat be set at theta to x-direction

+theta=asind(1/3)  //degree

+printf("The boat should be set in the direction theta=%.2f degree and time required is t=%.2f min\nDistance moved in downstream direction=%.2f m",theta,t,d)

+

+

diff --git a/3886/CH14/EX14.6/14_6.txt b/3886/CH14/EX14.6/14_6.txt
new file mode 100644
index 000000000..12c71bd1f
--- /dev/null
+++ b/3886/CH14/EX14.6/14_6.txt
@@ -0,0 +1,4 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.6.sce', -1)

+The boat should be set in the direction theta=19.47 degree and time required is t=4.00 min

+Distance moved in downstream direction=333.33 m
\ No newline at end of file
diff --git a/3886/CH14/EX14.7/14_7.sce b/3886/CH14/EX14.7/14_7.sce
new file mode 100644
index 000000000..152de87a0
--- /dev/null
+++ b/3886/CH14/EX14.7/14_7.sce
@@ -0,0 +1,23 @@
+//ship approaching port

+//refer fig. 14.13 and 14.14

+//let west be x and north be y axes 

+//speed in kmph is 

+vBx=25*sind(45)

+vBy=25*cosd(45)

+vAx=-15

+vAy=0

+//Let vr be the relative velocity of B w.r.t. A

+vrx=17.678-(-15)  //kmph

+vry=17.678   //kmph

+vr=sqrt((32.678^2)+(17.678^2))  //kmph

+alpha=atand(17.678/32.678)  //degree

+t=(50*cosd(alpha))/(vr)  //hours

+//during this time A has moved in east by (da)

+da=15*1.1837  //km

+//and B has moved in N 45 degree W a distance (db)

+db=25*1.1837  //km

+printf("\nt=%.2f hours\nA has moved in east by da=%.2f km\nB has moved in N 45 degree W a distance db=%.2f km",t,da,db)

+

+

+

+

diff --git a/3886/CH14/EX14.7/14_7.txt b/3886/CH14/EX14.7/14_7.txt
new file mode 100644
index 000000000..44e21c7b4
--- /dev/null
+++ b/3886/CH14/EX14.7/14_7.txt
@@ -0,0 +1,6 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.7.sce', -1)

+

+t=1.18 hours

+A has moved in east by da=17.76 km

+B has moved in N 45 degree W a distance db=29.59 km
\ No newline at end of file
diff --git a/3886/CH14/EX14.8/14_8.sce b/3886/CH14/EX14.8/14_8.sce
new file mode 100644
index 000000000..2d76b882b
--- /dev/null
+++ b/3886/CH14/EX14.8/14_8.sce
@@ -0,0 +1,31 @@
+//ship B approaching port

+//refer fig. 14.15 and 14.16

+//Considering west as x-axis and south as y-axis

+vAx=24*cosd(30)

+vAy=24*sind(30)

+vBx=-18

+vBy=0

+//Let relative velocity of A w.r.t. B be vr at an angle alpha to western direction

+vrx=vAx-vBx  //kmph

+vry=vAy-vBy

+v=sqrt((vrx)^2+(vry)^2)  //kmph

+alpha=atand(vry/vrx)  //degree

+//Holding B stationary and allowing A to move with relative velovity,BC is given by

+BC=60*sind(alpha)  //km

+//from triangle BCD

+DC=sqrt((25^2)+(17.735)^2)  //km

+CE=DC  //km

+AC=60*cosd(alpha)  //km

+AD=AC-DC  //km

+AE=AC+CE  //km

+//Time taken to reach D

+t1=39699*60/40899  //min

+//time taken to reach E

+t2=74939*60/40599  //min

+printf("\nThe two ships can start exchanging signals %.2f min after ship A leaves the port and continue to do so for %.2f min",t1,t2-t1)

+

+

+

+

+

+

diff --git a/3886/CH14/EX14.8/14_8.txt b/3886/CH14/EX14.8/14_8.txt
new file mode 100644
index 000000000..b6ba50eaa
--- /dev/null
+++ b/3886/CH14/EX14.8/14_8.txt
@@ -0,0 +1,4 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.8.sce', -1)

+

+The two ships can start exchanging signals 58.24 min after ship A leaves the port and continue to do so for 52.51 min
\ No newline at end of file
diff --git a/3886/CH14/EX14.9/14_9.sce b/3886/CH14/EX14.9/14_9.sce
new file mode 100644
index 000000000..58ff6af69
--- /dev/null
+++ b/3886/CH14/EX14.9/14_9.sce
@@ -0,0 +1,18 @@
+//passenger observing rain drops

+//refer fig. 14.17 

+//Let the true velocity of rain be v kmph at a true angle theta with vertical

+//Taking the direction of train as x and that of vertical downward as y

+//Velocity components of train are

+//v1x=v*sind(theta)

+//v1y=v*cosd(theta)

+//when the velocity of train was 36 kmph

+v2x=36

+v2y=0

+//alpha is the direction of relative velocity and is given as 30 degree and when the velocity of train is 54 kmph alpha=45 degree thus

+//v*cosd(theta)=v*sind(theta)-54

+//v*sind(theta)=-11.402

+//solving we get

+v=sqrt(4407.43)  //kmph

+theta=asind(-(11.402)/(66.388))

+printf("\nv=%.3f kmph\ntheta=%.2f degree",v,theta)

+

diff --git a/3886/CH14/EX14.9/14_9.txt b/3886/CH14/EX14.9/14_9.txt
new file mode 100644
index 000000000..13e7c8ac8
--- /dev/null
+++ b/3886/CH14/EX14.9/14_9.txt
@@ -0,0 +1,5 @@
+ 

+--> exec('E:\My program EM\14.Relative velocity\14.9.sce', -1)

+

+v=66.388 kmph

+theta=-9.89 degree
\ No newline at end of file