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+//===========================================================================
+//chapter 5 example 14
+clc;clear all;
+
+//variable declaration
+V      =   250;     //voltage in V
+RA    = 100;            //resistance in  Ω
+RB    = 400;            //resistance in  Ω
+x     = 0.005;        //error in measuring voltage in 
+
+
+//calculations
+I     = V/(RA+RB);     //current flowing through resistance in A
+VB    = I*RB;              //potential drop acreoss resitance in V
+//Req   = RA+((r*RB)/(r+RB))
+//Ieq    =V/Req  = V/ RA+((r*RB)/(r+RB))
+//Ieq   = (V*(r+RB))/((RA*(r+RB))+(r*RB))
+//V1 = Ieq*(r*RB)/(r+RB)
+// V1  = (V*(r+RB))*(r*RB))/((r+RB)*((RA*(r+RB))+(r*RB)))
+//V1   = (V*r*RB)/((r+RB)*((RA*(r+RB))+(r*RB)))
+//V1   = (200*r)/(80+r)
+V1   = VB*(1-x);     //voltage measured with 0.5% error
+r     = (V1*80)/(200-V1);       //solving equations  we get minimum resistance in Ω
+
+//result
+mprintf("minimum resistance = %3.2f Ω",r);
+