diff options
Diffstat (limited to '3841/CH7')
-rw-r--r-- | 3841/CH7/EX7.1/Ex7_1.sce | 16 | ||||
-rw-r--r-- | 3841/CH7/EX7.2/Ex7_2.sce | 9 | ||||
-rw-r--r-- | 3841/CH7/EX7.3/Ex7_3.sce | 10 | ||||
-rw-r--r-- | 3841/CH7/EX7.4/Ex7_4.sce | 13 | ||||
-rw-r--r-- | 3841/CH7/EX7.5/Ex7_5.sce | 10 | ||||
-rw-r--r-- | 3841/CH7/EX7.6/Ex7_6.sce | 8 | ||||
-rw-r--r-- | 3841/CH7/EX7.7/Ex7_7.sce | 12 | ||||
-rw-r--r-- | 3841/CH7/EX7.8/Ex7_8.sce | 9 | ||||
-rw-r--r-- | 3841/CH7/EX7.9/Ex7_9.sce | 10 |
9 files changed, 97 insertions, 0 deletions
diff --git a/3841/CH7/EX7.1/Ex7_1.sce b/3841/CH7/EX7.1/Ex7_1.sce new file mode 100644 index 000000000..82896f0d7 --- /dev/null +++ b/3841/CH7/EX7.1/Ex7_1.sce @@ -0,0 +1,16 @@ +clear +//given +// +//find the brake horse power +N=1150. +Wt=151. +l=4. +Wo=22. +//finding netforce +//f=Wt-Wo +F=Wt-Wo +//then as +R=4. +//calculating Brake horse power +Bhp=F*R*N/(5250.) +printf("\n \n braking horse power %.2f bhp",Bhp) diff --git a/3841/CH7/EX7.2/Ex7_2.sce b/3841/CH7/EX7.2/Ex7_2.sce new file mode 100644 index 000000000..60ff1bb43 --- /dev/null +++ b/3841/CH7/EX7.2/Ex7_2.sce @@ -0,0 +1,9 @@ +clear +//given +//find out what is torque produced by and engine +N=850. +bhp=62. +//by writting terms in equation +//5250 is dividing equation +T=5250*bhp/(N) +printf("\n \n torque produced by an engine %.2f lb-ft",T) diff --git a/3841/CH7/EX7.3/Ex7_3.sce b/3841/CH7/EX7.3/Ex7_3.sce new file mode 100644 index 000000000..6a0392d06 --- /dev/null +++ b/3841/CH7/EX7.3/Ex7_3.sce @@ -0,0 +1,10 @@ +clear +//given +//find out brake mean effective pressure of a 6-cylinder +D=5**0.75 +bhp=120. +l=8. +m=6. +n=1000. +bmep=1008000*((bhp/(D**2)*l*m*n)) +printf("\n \n brake mean effective pressure %.2f psi",bmep/2.95) diff --git a/3841/CH7/EX7.4/Ex7_4.sce b/3841/CH7/EX7.4/Ex7_4.sce new file mode 100644 index 000000000..b0d45893a --- /dev/null +++ b/3841/CH7/EX7.4/Ex7_4.sce @@ -0,0 +1,13 @@ +clear +//compute brake mean effective pressure +//given +T=350. +D=4**0.25 +L=5 +M=4 +//bmep for 4-cycle engine=192*t +bmep=192*(T/(D**2)*L*M) +//bmep for 2-cycle engine +bmep2=bmep/2 +printf("\n \n bmep for 4-cycle %.2f psi",bmep) +printf("\n \n bmep for 2-cycle %.2f psi",bmep) diff --git a/3841/CH7/EX7.5/Ex7_5.sce b/3841/CH7/EX7.5/Ex7_5.sce new file mode 100644 index 000000000..2b6dcf736 --- /dev/null +++ b/3841/CH7/EX7.5/Ex7_5.sce @@ -0,0 +1,10 @@ +clear +//given +//find out mechanical efficency of an engine +bhp=57. +ihp=19. +ihp1=ihp+bhp + +//computing according to equtaion +Me=(bhp/ihp1)*100. +printf("\n \n mechanical efficency %.2f percent",Me) diff --git a/3841/CH7/EX7.6/Ex7_6.sce b/3841/CH7/EX7.6/Ex7_6.sce new file mode 100644 index 000000000..74900ac7d --- /dev/null +++ b/3841/CH7/EX7.6/Ex7_6.sce @@ -0,0 +1,8 @@ +clear +//find the mechanical efficency of the diesel engine +//fid we set forth constant +fhp=19 +bhp=57/2. +ihp=bhp+fhp +Bhp=(bhp/ihp)*100 +printf("\n \n mechanical efficeny %.2f bhp",Bhp) diff --git a/3841/CH7/EX7.7/Ex7_7.sce b/3841/CH7/EX7.7/Ex7_7.sce new file mode 100644 index 000000000..71e3a0d6f --- /dev/null +++ b/3841/CH7/EX7.7/Ex7_7.sce @@ -0,0 +1,12 @@ +clear +//find the brake thermal efficency of an engine +//given +w=16.2 +t=20. +p=126. +q=19300. +//during 20 minutes period of the test 126 bhp for a period 1/3 hour 126*(1/3.) +btu=42.*2544. +hi=16.2*19300. +bth=(btu/hi)*100. +printf("\n \n brake thermal efficency %.2f percent",bth) diff --git a/3841/CH7/EX7.8/Ex7_8.sce b/3841/CH7/EX7.8/Ex7_8.sce new file mode 100644 index 000000000..368d41dde --- /dev/null +++ b/3841/CH7/EX7.8/Ex7_8.sce @@ -0,0 +1,9 @@ +clear +//find the brake thermal efficency +//given +f=0.44 +q=19500 +//for each bhp output is 2544 +hi=f*q +bth=(2544./hi)*100. +printf("\n \n brake thermal efficency %.2f bhp",bth) diff --git a/3841/CH7/EX7.9/Ex7_9.sce b/3841/CH7/EX7.9/Ex7_9.sce new file mode 100644 index 000000000..a30e90758 --- /dev/null +++ b/3841/CH7/EX7.9/Ex7_9.sce @@ -0,0 +1,10 @@ +clear +//find fuel consumption when using fuel 18 +//given +bth=38. +//calculating heat input +//1 bhp 2544 +hi=(2544./bth)*100. +printf("\n \n heat input %.2f btu per hp",hi) +F=hi/18390. +printf("\n \n fuel consumption %.2f lb",F) |