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+clear
+//
+//the following problem is based on usage of superposition theorem
+i8=12/(6+4+8) //current for 8 ohm resistor.the resistances are in series with each other.Hence 6+4+8
+//next when voltage source is short circuited (8+4) total of resistance is obtained.The 4A is distributed in parallel branches as per current divider rule
+i=(4*6)/(6+12)
+printf("\n i8= %0.1f A",i8)
+printf("\n i8= %0.1f A",i)
+tot=i8+i
+printf("\n total current= %0.1f A",tot)
+
+