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+// Example 16_1
+clc;funcprot(0);
+// Given data
+T=20+273.15;// K
+V=90.0;// km/h
+g_c=1;// The gravitational constant
+c_p=1.004;// kJ/kg.K
+
+// Solution
+T_0=T*(1+(((V*10^3/(3600*1000))^2)/(2*g_c*c_p*T)));// K
+T_0=T_0-273.15;// °C
+printf("\nThe stagnation temperature,T_0=%2.1f°C",T_0)