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Diffstat (limited to '3830/CH1/EX1.15/Ex1_15.sce')
-rw-r--r-- | 3830/CH1/EX1.15/Ex1_15.sce | 29 |
1 files changed, 29 insertions, 0 deletions
diff --git a/3830/CH1/EX1.15/Ex1_15.sce b/3830/CH1/EX1.15/Ex1_15.sce new file mode 100644 index 000000000..febb9fc98 --- /dev/null +++ b/3830/CH1/EX1.15/Ex1_15.sce @@ -0,0 +1,29 @@ +// Exa 1.15
+
+clc;
+clear;
+
+// Given
+
+// Refer fig. 1.73
+Rtotal = 11*10^6; // Total resistance in Ohms
+Vg = 1; // Voltage at gate of balancing circuit
+Vmax = 1000; // Max voltage in Volts
+// Solution
+
+printf('When the selector switch is at 1000 V position, and the mass input is 1000 V, the drop across R7 should be 1 value \n');
+R7 = (Vg/Vmax)*Rtotal;
+printf('R7 = %d k Ohms \n',R7/1000);
+printf('Similarly, when the selector switch is at the 300 V position, the drop across (R6+R7) should be 1 V \n');
+R6 = (Vg/300)*Rtotal-R7;
+printf('R6 = %.2f k Ohms \n',R6/1000);
+R5 = (Vg/100)*Rtotal-(R7+R6);
+printf('R5 = %.2f k Ohms \n',R5/1000);
+R4 = (Vg/30)*Rtotal-(R7+R6+R5);
+printf('R4 = %.2f k Ohms \n',R4/1000);
+R3 = (Vg/10)*Rtotal-(R7+R6+R5+R4);
+printf('R3 = %.2f k Ohms \n',R3/1000);
+R2 = (Vg/3)*Rtotal-(R7+R6+R5+R4+R3);
+printf('R2 = %.2f k Ohms \n',R2/1000);
+R1 = Rtotal - (R2+R3+R4+R5+R6+R7);
+printf('R1 = %.2f k Ohms \n',R1/1000);
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